15. (D- 1) (D+3)(D² + 2D + 5)²[y]
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![15. (D - 1)2(D+ 3)(D² + 2D + 5)²[y] = 0
16. (D+ 1)²(D- 6) (D+5)(D² +1) (D² + 4)[y] = 0
17. (D+ 4)(D- 3)(D+2)°(D² + 4D + 5)²D°[y] = 0
18. (D - 1) (D- 2)(D² + D + 1)
• (D² + 6D + 10) [y] = 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F498817a5-9d87-445d-98c6-fd7f0a99e617%2Ff313756f-02a3-4280-9097-056dff06d533%2Fl8f54qe_processed.jpeg&w=3840&q=75)
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- how would I take the partial derrivitive of this equation, I cannot use the chain Rule as we have not learned it yet, the teacher said we would have to manipulate the equation somehow. f(x,y) = x2 ln(2y3 -x4)Solid inside x2 + y2 + z2 = 16 and outside z = √x2 + y2(1-xy)-2dx+[y2+x2(1-xy)-2]dy=0 when x=2, y=1
- Find the work done in emptying the tank in example 4. If the tank water is pumped to a level 1.00 meters above the top of the tank and the water is initially 4.00 meters deep.find the first and second derivatives w = 3z7 - 7z3 + 21z2The assembly for this problem for model S is 0.4 and for model LX 0.5. Can you redo the problem with this information correct?