15. The half-life of carbon-14 is 5770 years. Assuming you start with 100 percent of carbon-14, what is the expression for the percent, P(t), of carbon-14 that will remain in an organism that is t years old, and what is the percent of carbon-14 remaining (rounded to the nearest whole percent) in an organism that is estimated to be 15000 years old? Hint: The exponential equation for half-life is P(t) = A₁ (0.5)¹/h, where P(t) is the percent of carbon-14 remaining, A, is the initial amount (100%), t is age of the organism in years, and H is the half-life. P(t) = 5770(0.5)100/€, 5730 remaining P(t) = 100(0.5)/5770, 16% remaining P(t) = 100(0.5)5770/t, 84% remaining P(t) = 100(0.5)5770€, 16% remaining
15. The half-life of carbon-14 is 5770 years. Assuming you start with 100 percent of carbon-14, what is the expression for the percent, P(t), of carbon-14 that will remain in an organism that is t years old, and what is the percent of carbon-14 remaining (rounded to the nearest whole percent) in an organism that is estimated to be 15000 years old? Hint: The exponential equation for half-life is P(t) = A₁ (0.5)¹/h, where P(t) is the percent of carbon-14 remaining, A, is the initial amount (100%), t is age of the organism in years, and H is the half-life. P(t) = 5770(0.5)100/€, 5730 remaining P(t) = 100(0.5)/5770, 16% remaining P(t) = 100(0.5)5770/t, 84% remaining P(t) = 100(0.5)5770€, 16% remaining
Chapter6: Exponential And Logarithmic Functions
Section: Chapter Questions
Problem 29PT: A radiation safety officer is working with 112 grams of a radioactive substance. After 17 days,...
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Transcribed Image Text:15. The half-life of carbon-14 is 5770 years. Assuming you start with 100 percent of carbon-14, what is the expression for the percent, P(t), of carbon-14 that will remain in an organism that
is t years old, and what is the percent of carbon-14 remaining (rounded to the nearest whole percent) in an organism that is estimated to be 15000 years old?
Hint: The exponential equation for half-life is P(t) = A₁(0.5)t/h, where P(t) is the percent of carbon-14 remaining, A is the initial amount (100%), t is age of the organism in years,
and H is the half-life.
P(t) = 5770(0.5)¹00/t, 5730 remaining
P(t) = 100(0.5)¹/5770, 16% remaining
P(t) = 100(0.5)5770/t, 84% remaining
P(t) = 100(0.5)5770, 16% remaining
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