16- specifications of step response can be found from drop-down menu by right click on background on the figure window with select: a) properties b) characteristics c) normalize d) systems

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16- specifications of step response can be found from drop-down menu by right click on background on
the figure window with select:
a) properties
b) characteristics
c) normalize
d) systems
17- Three different 1st order systems have the following roots in denominator:
S₁ = -0.2, S₂ = -0.4, S₂ = -0.6 which system has the fastest step response?
a) The system with S₁
b) The system with S2
c) The system with S3
d) No one of the above answers
18- If a transfer function G(s) is entered as
the system G(s) is:
a) s= tf('s'); G= (s+1)/((s+2)*(s+3))
b)
s= tf(s); G= (s+1)/((s+2)*(s+3))
S+1
(s²+2s+5)
the command to find the impulse response of
c) s= tf('s'); G= (s+1)/(s+2)*(s+3)
d) s= tf(s); G= (s+1)/(s+2)*(s+3))
19- The Matlab command to find the ramp response curve of the following system transfer function
2s+1
G(s)=
is entered as:
s²+s+1
a) t= [0:0.1:10]; r(t) = t; Isim([2, 1];[1, 1, 1], r(t), t)
b) t= [0:0.1:10]; r = t; Isim([2, 1],[1, 1, 1], r, t)
c)
Isim ([2, 1],[1, 1, 1],[0;0.1;10], [0:0.1:10])
d)
Isim ([2, 1],[1, 1, 1],[0:0.1:10], [0:0.1:10])
20- The closed loop system with the following transfer functions G(s)= and H(s) 2 cannot be
reduced to overall transfer function if using:
a) G=tf(1,[1, 2]), sys=feedback (G,2)
b) s= tf('s'), G= 1/(s+2), H=2, sys=feedback(G,H)
c) sys=feedback(tf(1,[1, 2]), 2)
d) sys=feedback(tf(1,[1.2]),2)
1
S+2
Transcribed Image Text:16- specifications of step response can be found from drop-down menu by right click on background on the figure window with select: a) properties b) characteristics c) normalize d) systems 17- Three different 1st order systems have the following roots in denominator: S₁ = -0.2, S₂ = -0.4, S₂ = -0.6 which system has the fastest step response? a) The system with S₁ b) The system with S2 c) The system with S3 d) No one of the above answers 18- If a transfer function G(s) is entered as the system G(s) is: a) s= tf('s'); G= (s+1)/((s+2)*(s+3)) b) s= tf(s); G= (s+1)/((s+2)*(s+3)) S+1 (s²+2s+5) the command to find the impulse response of c) s= tf('s'); G= (s+1)/(s+2)*(s+3) d) s= tf(s); G= (s+1)/(s+2)*(s+3)) 19- The Matlab command to find the ramp response curve of the following system transfer function 2s+1 G(s)= is entered as: s²+s+1 a) t= [0:0.1:10]; r(t) = t; Isim([2, 1];[1, 1, 1], r(t), t) b) t= [0:0.1:10]; r = t; Isim([2, 1],[1, 1, 1], r, t) c) Isim ([2, 1],[1, 1, 1],[0;0.1;10], [0:0.1:10]) d) Isim ([2, 1],[1, 1, 1],[0:0.1:10], [0:0.1:10]) 20- The closed loop system with the following transfer functions G(s)= and H(s) 2 cannot be reduced to overall transfer function if using: a) G=tf(1,[1, 2]), sys=feedback (G,2) b) s= tf('s'), G= 1/(s+2), H=2, sys=feedback(G,H) c) sys=feedback(tf(1,[1, 2]), 2) d) sys=feedback(tf(1,[1.2]),2) 1 S+2
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