Write a program to create a dictionary to store assets, liabilities and capital of a company. After creating the dictionary display, assets and liabilities of the company and test if the accounting equation holds true.
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- Assume the variable dct references a dictionary. Write an if statement that determines whetherthe key 'James' exists in the dictionary. If so, display the value that is associated with that key.If the key is not in the dictionary, display a message indicating so.# PART 1 - Complete the function below to deocompose# a compound formula written as a string# in a dictionary###################################################### def mol_form(compound_formula): """(str) -> dictionary When passed a string of the compound formula, returns a dictionary with the elements as keys and the number of atoms of that element as values. >>> mol_form("C2H6O") {'C': 2, 'H': 6, 'O': 1} >>> mol_form("CH4") {'C': 1, 'H': 4} """This is my code for a dictionary of student's test scores. def main(): #Create a dictionary with name as key #Marks as the list of values student_dictionary = \ { 'Brian': [94, 89, 92], 'Rachel': [100,90,65], 'Jon': [67.5,95,100], 'Brit': [0,78,80] , 'Gret': [65,100,78], 'Andrea': [55.5,67,79] } for key in student_dictionary.keys(): print('Name: ', key, " , Marks:", student_dictionary.get(key)) if __name__ == '__main__': main() Problem: Find and print out Rachels second score (should be a 90)
- Code the following directions in python: 1.Write a statement that creates a dictionary containing the following key-value pairs: 'a' : 1 'b' : 2 'c' : 3 2.Write a statement that creates an empty dictionary. 3.Assume the variable dct references a dictionary. Write an if statement that determines whether the key 'James' exists in the dictionary. If so, display the value that is associated with that key. If the key is not in the dictionary, display a message indicating so.Assume the following list exists: names = ['Chris', 'Katie', 'Joanne', 'Kurt'] Write a statement that uses a dictionary comprehension to create a dictionary named X in which each element contains the length of a name from the list as the key, and the corresponding name's initial character as its value.# PART 1 - Complete the function below to deocompose# a compound formula written as a string# in a dictionary######################################################import chemparse def mol_form(compound_formula): """(str) -> dictionary When passed a string of the compound formula, returns a dictionary with the elements as keys and the number of atoms of that element as values. >>> mol_form("C2H6O") {'C': 2, 'H': 6, 'O': 1} >>> mol_form("CH4") {'C': 1, 'H': 4} """ print((chemparse.parse_formula(compound_formula))) mol_form("C2H6O")mol_form("CH4") ####################################################### PART 2 - Complete the function below that takes two # tuples representing one side of a# chemical equation and returns a dictionary# with the elements as keys and the total# number of atoms in the entire expression# as values.######################################################…
- # PART 1 - Complete the function below to deocompose# a compound formula written as a string# in a dictionary######################################################import chemparse def mol_form(compound_formula): """(str) -> dictionary When passed a string of the compound formula, returns a dictionary with the elements as keys and the number of atoms of that element as values. >>> mol_form("C2H6O") {'C': 2, 'H': 6, 'O': 1} >>> mol_form("CH4") {'C': 1, 'H': 4} """ print((chemparse.parse_formula(compound_formula))) mol_form("C2H6O")mol_form("CH4") ####################################################### PART 2 - Complete the function below that takes two # tuples representing one side of a# chemical equation and returns a dictionary# with the elements as keys and the total# number of atoms in the entire expression# as values.######################################################…# PART 1 - Complete the function below to deocompose# a compound formula written as a string# in a dictionary######################################################import chemparse def mol_form(compound_formula): """(str) -> dictionary When passed a string of the compound formula, returns a dictionary with the elements as keys and the number of atoms of that element as values. >>> mol_form("C2H6O") {'C': 2, 'H': 6, 'O': 1} >>> mol_form("CH4") {'C': 1, 'H': 4} """ print((chemparse.parse_formula(compound_formula))) mol_form("C2H6O")mol_form("CH4") ####################################################### PART 2 - Complete the function below that takes two # tuples representing one side of a# chemical equation and returns a dictionary# with the elements as keys and the total# number of atoms in the entire expression# as values.######################################################…8.25 LAB: Car wash Write a program to calculate the total price for car wash services. A base car wash is $10. A dictionary with each additional service and the corresponding cost has been provided. Two additional services can be selected. A '-' signifies an additional service was not selected. Output all selected services along with the corresponding costs and then the total price for all car wash services. Ex: If the input is: Tire shine Wax the output is: ZyCar Wash Base car wash -- $10 Tire shine -- $2 Wax -- $3 ---- Total price: $15 Ex: If the input is: Rain repellent - the output is: ZyCar Wash Base car wash -- $10 Rain repellent -- $2 ---- Total price: $12 Use Python, please.
- 8.25 LAB: Car wash Write a program to calculate the total price for car wash services. A base car wash is $10. A dictionary with each additional service and the corresponding cost has been provided. Two additional services can be selected. A '-' signifies an additional service was not selected. Output all selected services along with the corresponding costs and then the total price for all car wash services. Ex: If the input is: Tire shine Wax the output is: ZyCar Wash Base car wash -- $10 Tire shine -- $2 Wax -- $3 ---- Total price: $15 Ex: If the input is: Rain repellent - the output is: ZyCar Wash Base car wash -- $10 Rain repellent -- $2 ---- Total price: $12 this is the code that im supposed to follow up on services = { 'Air freshener' : 1 , 'Rain repellent': 2, 'Tire shine' : 2, 'Wax' : 3, 'Vacuum' : 5 }base_wash = 10total = 0 service_choice1 = input()service_choice2 = input() ''' Type your code here '''void dict_clear (dict_t* dict); This function clears the dictionary dict, destroying each pair key/value, but does not destroy dict itself (remember that dict was allocated using dict_create, so it will need to be freed at some point, but this is not this function’s job.) This is now the function that frees (destroys) a dictionary: void dict_destroy (dict_t* dict); This operates just as dict_clear, but in addition should free the memory that was allocated during dict_create. After a call to this function, if any other library function receives the pointer dict, the behavior is undefined (most likely, it will crash). This simple function returns the current size of the dictionary: size_t dict_size (const dict_t* dict);Data structures dict_contains_keys(items:set, example_dict:dict)->bool This function will have two parameters. The first is a set of numbers known as Number Set. The second is a dictionary known as Dictionary. Dictionary will have keys as integers and values as letters. The functions should return true if at least one of the numbers in the Number set is a key in Dictionary. It should return false otherwise. Example: Items: {8, 10, 5} Example: {9: 'F', 10: 'X'} Expected: True Items: {8, 9, 5, 1} Example: {6: 'i', 5: 'Y', 1: 'N', 0: 'E'} Expected: True Items: {9, 10, 4} Example: {5: 'i', 3: 'o', 1: 'N'} Expected: False