[ 17 ] : 1.23 c = Ex: 1.23

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter5: Orthogonality
Section: Chapter Questions
Problem 15RQ
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Question
X Each incorrect answer is highlighted.
3
}
-60
1.48
Expected: { vi
4
V2
45
, V3
-1.11
100
1.39
3
Vi = uj =
4
(u2, v1)
V2 = u2
V1
(V1, V1)
3.
(-125)
4
-75
25
25
100
-60
45
100
(u3, V1)
V1
(V1, V1)
(u3, V2)
V2
(v2, v2)
V3 = u3
-60
3.
(-1)
4
25
1
95
45
-
15625
2
100
1.48
-1.11
1.39
-60
1.48
An orthogonal basis is
Vi =
V2 =
45
V3 =
-1.11
100
1.39
||
Transcribed Image Text:X Each incorrect answer is highlighted. 3 } -60 1.48 Expected: { vi 4 V2 45 , V3 -1.11 100 1.39 3 Vi = uj = 4 (u2, v1) V2 = u2 V1 (V1, V1) 3. (-125) 4 -75 25 25 100 -60 45 100 (u3, V1) V1 (V1, V1) (u3, V2) V2 (v2, v2) V3 = u3 -60 3. (-1) 4 25 1 95 45 - 15625 2 100 1.48 -1.11 1.39 -60 1.48 An orthogonal basis is Vi = V2 = 45 V3 = -1.11 100 1.39 ||
-68
2
Let
u2
, U3
be a basis for R. Use the Gram-Schmidt process to
17
3
find an orthogonal basis under the Euclidean inner product.
4
-20
a
Orthogonal basis: { vi =
V2
V3 =
17
a = Ex: 1.23C
b:
Ex: 1.23
c = Ex: 1.23
Transcribed Image Text:-68 2 Let u2 , U3 be a basis for R. Use the Gram-Schmidt process to 17 3 find an orthogonal basis under the Euclidean inner product. 4 -20 a Orthogonal basis: { vi = V2 V3 = 17 a = Ex: 1.23C b: Ex: 1.23 c = Ex: 1.23
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