17. 4 0 0 1 4 0 0 05

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.3: Eigenvalues And Eigenvectors Of N X N Matrices
Problem 41EQ
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Linear algebra 

17 pl

, and v₂
fA. Use this information to diagonalize A.
rix with eigenvalues 5, 3, and -2, and suppose you know that
= 3 is two-dimensional. Do you have enough information
gonalizable?
V₁ =
5.
6.
2 2 17
1
1
1
1
1
4
2
0
-2
0
1
232
1
2_
-1
1 2
0 -1
5
+][
0
H
0-2
5
4
05
0 00
0
1
0 -171
1
2
0
0
1
05
5
0 0
96
011/4
0 1/4
5 00
1/2 1/47
1/2-3/4
[1/4-1/2 1/4_
0
I
4
0
2
to
-1
ei einer
0 17
1 4
0-2
Diagonalize the matrices in Exercises 7-20, if possible. The
eigenvalues for Exercises 11-16 are as follows: (11) λ = 1,2,3;
(12) λ = 2,8; (13) λ = 5, 1; (14) λ = 5, 4; (15) λ = 3,1; (16)
λ = 2, 1. For Exercise 18, one eigenvalue is λ = 5 and one
eigenvector is (-2, 1, 2).
Transcribed Image Text:, and v₂ fA. Use this information to diagonalize A. rix with eigenvalues 5, 3, and -2, and suppose you know that = 3 is two-dimensional. Do you have enough information gonalizable? V₁ = 5. 6. 2 2 17 1 1 1 1 1 4 2 0 -2 0 1 232 1 2_ -1 1 2 0 -1 5 +][ 0 H 0-2 5 4 05 0 00 0 1 0 -171 1 2 0 0 1 05 5 0 0 96 011/4 0 1/4 5 00 1/2 1/47 1/2-3/4 [1/4-1/2 1/4_ 0 I 4 0 2 to -1 ei einer 0 17 1 4 0-2 Diagonalize the matrices in Exercises 7-20, if possible. The eigenvalues for Exercises 11-16 are as follows: (11) λ = 1,2,3; (12) λ = 2,8; (13) λ = 5, 1; (14) λ = 5, 4; (15) λ = 3,1; (16) λ = 2, 1. For Exercise 18, one eigenvalue is λ = 5 and one eigenvector is (-2, 1, 2).
, and v₂
fA. Use this information to diagonalize A.
rix with eigenvalues 5, 3, and -2, and suppose you know that
= 3 is two-dimensional. Do you have enough information
gonalizable?
V₁ =
5.
6.
2 2 17
1
1
1
1
1
4
2
0
-2
0
1
232
1
2_
-1
1 2
0 -1
5
+][
0
H
0-2
5
4
05
0 00
0
1
0 -171
1
2
0
0
1
05
5
0 0
96
011/4
0 1/4
5 00
1/2 1/47
1/2-3/4
[1/4-1/2 1/4_
0
I
4
0
2
to
-1
ei einer
0 17
1 4
0-2
Diagonalize the matrices in Exercises 7-20, if possible. The
eigenvalues for Exercises 11-16 are as follows: (11) λ = 1,2,3;
(12) λ = 2,8; (13) λ = 5, 1; (14) λ = 5, 4; (15) λ = 3,1; (16)
λ = 2, 1. For Exercise 18, one eigenvalue is λ = 5 and one
eigenvector is (-2, 1, 2).
Transcribed Image Text:, and v₂ fA. Use this information to diagonalize A. rix with eigenvalues 5, 3, and -2, and suppose you know that = 3 is two-dimensional. Do you have enough information gonalizable? V₁ = 5. 6. 2 2 17 1 1 1 1 1 4 2 0 -2 0 1 232 1 2_ -1 1 2 0 -1 5 +][ 0 H 0-2 5 4 05 0 00 0 1 0 -171 1 2 0 0 1 05 5 0 0 96 011/4 0 1/4 5 00 1/2 1/47 1/2-3/4 [1/4-1/2 1/4_ 0 I 4 0 2 to -1 ei einer 0 17 1 4 0-2 Diagonalize the matrices in Exercises 7-20, if possible. The eigenvalues for Exercises 11-16 are as follows: (11) λ = 1,2,3; (12) λ = 2,8; (13) λ = 5, 1; (14) λ = 5, 4; (15) λ = 3,1; (16) λ = 2, 1. For Exercise 18, one eigenvalue is λ = 5 and one eigenvector is (-2, 1, 2).
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