- 17+t = 3t- 7

Q: -9=x-4

A: -9 + 9 = x - 4 + 9

Q: The : /2-

A: Q

Q: -5a? – x = 0

A:

Q: -18 + 4(6 ÷ 2)2

A: Given:

Q: y-2 =(x- (-5))

A: as per our company guidelines we are supposed to answer only first question. Kindly repost other…

Q: (c).xv-12-2≦y2

A:

Q: -2 r. -2 |= -5 %3D and

A:

Q: |-2r-1|=11

A:

Q: -8r - 5 --3(7r + 6)

A: Solved below

Q: Find y = 2x- 5 xp II

A:

Q: (c) 4x+16-3æ|+ 5, where r < 2

A: We have to find

Q: -4 4 T F ニ -5

A: As we know that -: -a/b=a/(-b) because it can be written as -1×(a/b)=a/(-1×b) It implies…

Q: -47. y = x²

A:

Q: (b) -+3r- 6|+ 2, where r > 2

A:

Q: (() -4 (T1 o T2)

A: In this question, we find the composition of transformations at a given vector.

Q: Evaluate 3t-4(2 + 4t-3)-7dt

A:

Q: -X – y = 5

A: The equation is -x - y = 5

Q: O y= x22x-3 メ+

A: Given that  y=√((x^2-2x-3)/(x+4)) To find the domain of y

Q: d. -2(x + 4) +6= -3

A:

Q: Find the value of a. -3t a VE Vs + 3

A:

Q: f(@) A B - - 2 2.

A:

Q: x? + V5 x – 6 = 0 2.

A:

Q: - 25+y=4xeズ

A:

Q: -5/2 y?-2y 4. -/2 - 2y 1/2

A:

Q: If t=-3, then 3r +5t+6 equals -36

A:

Q: (z - 4)2 + (y + 3)² = 25

A: we have to find the equation of circle with radius RG=5 and center :(4,-3).

Q: -48 = -3x X= ?

A: Consider the equation  −48=−3x

Q: -2x - y =12  9x+y = -26

A: The given equations are -2x - y =12     ....... (1) 9x+y = -26    ........ (2)

Q: Y^2+13y=-42

A:

Q: -10r+12s -6 S =

A:

Q: L{(2t-3)µ(t-2)}

A:

Q: ex² =e-5x-4

A: Given equation is ex2 = e-5x-4

Q: Find t 7t - 5 = 16

A: Given, 7t -5 = 16  We have to find the value of t.

Q: S= tan(エャ)-1 『3=(ス+2-1)) 6 メ= つう

A:

Q: Find A" for A -3 -27 :) A- [ 2) A 5 9 3 4-

A: To find A-1

Q: X+Z4-てて-5 二メ -34ト42:9 2メーツ tて。

A:

Q: - 6 = r-6. 3C

A: The given expression is: x-6=x-6

Q: 2) r- 6= 6 + 4r

A: The objective is to solve the equation.

Q: Subtract -2x'y? – 3x²y + 7 from 3x'y² – 4x°y – 3.

A: Subtract -2x5y2-3x3y+7 from 3x5y2-4x3y-3

Q: 응 +-름구 + 4z +C

A:

Q: (-x³y?)®

A: (-x5y7)6

Q: -5(3t+2)-(2t+7)-4t+9

A: The given expression is -5(3t+2)-(2t+7)-4t+9.

Q: (DA2D³ - 13D² +38D24)y = 0

A: We have to find the general solution of the differential equation D4-2D3-13D2+38D-24y=0 .

Q: (b) y =-10y,

A: The solution is given below :

Q: -3b - 7

A: Let assume that-3b - 7 = 0

Q: 3. (2x + j3y)? - 6 - j12 = 0

A: The given equation is  (2x + j3y)2 = 6 + j12. The main objective is to solve the given equation. The…

Q: S 4r - 2y - 20 - -16x 5y 28

A:

Q: State whether the equation z = (;)' + (;)* 2 2 7

A:

Q: Divide. y6 – 7y* - 49y - 14 7y? 4a – a² – 8 – (-4a")

A: Given query is to simplify the expressions.

Q: r(t) = (3t, 4 + 2t-t2)

A:

Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.