19) In the equation below, k is a constant. Which of the following inequalities represents all values of k for which the equation has two distinct real solutions? (Hint: use the discriminant; if b2 -4ac > 0, there are two real solutions) kx? +5x = -7 25 A. k<- 28 25 В. К>- 28 25 C. k<- 28 25 D. k>: 28

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
Problem 48PS
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Related questions
Question
Quadratic Applications Number 19
(2.x - 3)(x + 4) = U
Solve (2x-3) = 0 and (x+4) = 0 then substitute the answers in for a and b in -a-b
and x
17) In the equation below, m is a constant. If the equation has the solutions x =
what is the value of m?
Zx +5
(2x +5)(-mx + 9) = 0
- mY+9=6
Solve -m
+9=0
-3m 418=0
9 = 6474.
18) In the equation below, a is a constant. If the equation has the solutions x = 4 and x=-4, what is
the value of a ?
(x+4)(2x – a)= 0
Substitute x =4 into (2x - a) = 0 and solve for a.
19) In the equation below, k is a constant. Which of the following inequalities represents all values of k
for which the equation has two distinct real solutions? (Hint: use the discriminant; if b² – 4ac > 0 , there
are two real solutions)
lx? + 5x = -7
25
D. k>
28
25
25
A. k<-
28
25
B. k>-
28
C. k<-
28
Transcribed Image Text:(2.x - 3)(x + 4) = U Solve (2x-3) = 0 and (x+4) = 0 then substitute the answers in for a and b in -a-b and x 17) In the equation below, m is a constant. If the equation has the solutions x = what is the value of m? Zx +5 (2x +5)(-mx + 9) = 0 - mY+9=6 Solve -m +9=0 -3m 418=0 9 = 6474. 18) In the equation below, a is a constant. If the equation has the solutions x = 4 and x=-4, what is the value of a ? (x+4)(2x – a)= 0 Substitute x =4 into (2x - a) = 0 and solve for a. 19) In the equation below, k is a constant. Which of the following inequalities represents all values of k for which the equation has two distinct real solutions? (Hint: use the discriminant; if b² – 4ac > 0 , there are two real solutions) lx? + 5x = -7 25 D. k> 28 25 25 A. k<- 28 25 B. k>- 28 C. k<- 28
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