(19) x² + 2x + I (x +1) (x+1) = Cx+i)? x² = | (x²+ 2% +1) t 2x+1. 2+2x+1 y2 /x² + 2x +l 2x +1 x2 %3D x² +2X +1. 2x +| B Cx+1)2 -> (x+1)2 (x+1) ACXH) +B Ax +IA + B = 2x +1 → x(A) + IA +B = 2x+1 A = 2 A +B = | 2+8 = 1

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