Don't copy 1st Normal Form (1NF)Consider the Students table, with the primary key underlined,and the following data:Students:Students:GradePoints2,3,34.4EmailAlpha100111092244113221090112NameCoursesdoe@usna.edusmith@usna.edublack@usna.eduTom Johnson Johnson@usna.edu NN204, S1204, IT221John DoeMatt SmithNN204, S1204, IT221SM223, EEЗ01Melinda BlackS120434,2,3a) Is the Students table in 1NF? Why?b) If the Students table is not in 1NF, redesign the tables suchthat all the information currently in the Students table is foundin the resulting tables, and the resulting tables are in 1NF. Foreach of the resulting tables, give the table name, columnnames, primary keys, and foreign keys.

First Normal Form (1NF): => If a table includes a composite or multi-valued attribute, it…

1st Normal Form (1NF) Consider the Students table, with the primary key underlined, and the following data: Students: Students: Alpha 100111 092244 113221 Melinda Black 090112 Tom Johnson Email doe@usna.edu smith@usna.edu black@usna.edu Johnson@usna.edu NN204, S1204, IT221 Name John Doe Matt Smith Courses NN204, S1204, IT221 SM223, EE301 SI204 GradePoints 2,3,3 4.4 3 4,2,3 a) Is the Students table in 1NF? Why? b) If the Students table is not in 1NF, redesign the tables such that all the information currently in the Students table is found in the resulting tables, and the resulting tables are in 1NF. For each of the resulting tables, give the table name, column names, primary keys, and foreign keys.

1st Normal Form (1NF) Consider the Students table, with the primary key underlined, and the following data: Students: Students: Alpha 100111 092244 113221 Melinda Black 090112 Tom Johnson Email doe@usna.edu smith@usna.edu black@usna.edu Johnson@usna.edu NN204, S1204, IT221 Name John Doe Matt Smith Courses NN204, S1204, IT221 SM223, EE301 SI204 GradePoints 2,3,3 4.4 3 4,2,3 a) Is the Students table in 1NF? Why? b) If the Students table is not in 1NF, redesign the tables such that all the information currently in the Students table is found in the resulting tables, and the resulting tables are in 1NF. For each of the resulting tables, give the table name, column names, primary keys, and foreign keys.

Database Systems: Design, Implementation, & Management

12th Edition

ISBN:9781305627482

Author:Carlos Coronel, Steven Morris

Publisher:Carlos Coronel, Steven Morris

Chapter3: The Relational Database Model

Section: Chapter Questions

Problem 14P: Do the tables exhibit referential integrity? Answer yes or no, and then explain your answer. Write...

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You are given this table: Registration SID CourseID SemID Instructor Grade 282712 ENGL210 201701 H. Zacny B+ 362112 CS101 201701 K. Ross C 652123 CS403 201701 K. Ross A 362112 CS403 201701 K. Smith C+ 282712 BIO101 201601 I. Olsen C What will the result of the following query be? select sid, count(*)from registrationgroup by sid Select one: a. The entire table sorted by sid b. No results due to an error c. 282712 2362112 2652123 1 d. 282712 1362112 1652123 1
Use Mysql code The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results. Hint: Perform a join on the LessonSchedule, Student, and Horse tables, matching the student IDs and horse IDs.
Consider the following relations for a university: Student (sid: integer, sname: string(100 chars), GPA: real, dateOfBirth: date, Did: integer, FirstYear: integer)Department (did: integer, dname: string(30 chars), capacity: integer)Course (cid: integer, cname: string(50 chars), credit: integer)Enroll (studentID: integer, courseID: integer, departmentID: integer, enrollmentDate: date, finalGrade: real) studentID, courseID, and departmentID in Enroll are foreign keys referencing the primary keys of the student, course, and department relations, respectively. Did in Student is a foreign key referencing the primary key of the department relation. 1) For each student with GPA between 2.5 (included) and 3.5 (included), display the student’s name, GPA,and his/her department ID. Sort the results by the students’ IDs in descending order. 2) For each student who joined the Computer Science department between 2018 (included) and 2020(included), display the…
Write Mysql code for: The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results. Hint: Perform a join on the LessonSchedule, Student, and Horse tables, matching the student IDs and horse IDs.
The table STUDENT has the attributes STUDENT_ID, NAME, SCHOOL_ID, and ADDR. The table SCHOOL has the attributes SCHOOL_ID, NAME, and STATE_CODE. Assume that there is a 1:N relation between SCHOOL and STUDENT. Which of the following creates a table that shows the STUDENT attributes and the corresponding SCHOOL attributes? a. SELECT * SCHOOL_ID FROM STUDENT JOIN SCHOOL b. SELECT * SCHOOL_ID FROM STUDENT JOIN SCHOOL USING(SCHOOL_ID) c. SELECT * SCHOOL_ID FROM STUDENT NATURAL JOIN SCHOOL d. SELECT * SCHOOL_ID FROM STUDENT, SCHOOL WHERE SCHOOL_ID = SCHOOL_ID
SQL Table: CREATE TABLE employees ( employee_id INT PRIMARY KEY, first_name VARCHAR(255), last_name VARCHAR(255), email VARCHAR(255) UNIQUE, phone_number VARCHAR(255), hire_date DATE, job_id VARCHAR(255), salary DECIMAL(10,2), commission_pct DECIMAL(5,2), manager_id INT, department_id INT, FOREIGN KEY (manager_id) REFERENCES employees(employee_id), FOREIGN KEY (department_id) REFERENCES departments(department_id)); CREATE TABLE departments ( department_id INT PRIMARY KEY, department_name VARCHAR(255), manager_id INT, FOREIGN KEY (manager_id) REFERENCES employees(employee_id)); INSERT INTO employees (employee_id, first_name, last_name, email, phone_number, hire_date, job_id, salary, commission_pct, manager_id, department_id)VALUES (1, 'John', 'Doe', 'john.doe@example.com', '555-555-5555', '2022-01-01', 'IT_PROG', 8000, 0.2, 3, 10), (2, 'Jane', 'Smith', 'jane.smith@example.com', '555-555-5556', '2022-02-01', 'IT_PROG', 9000,…
The table STUDENT has the attributes STUDENT_ID, NAME, S_ID, and ADDR. The table SCHOOL has the attributes SCHOOL_ID, NAME, and STATE_CODE. Assume that there is a 1:N relation between SCHOOL and STUDENT where the common attributes are S_ID, and SCHOOL_ID. Which of the following creates a table that shows the STUDENT attributes and the corresponding SCHOOL attributes? a. SELECT * FROM STUDENT JOIN SCHOOL USING(SCHOOL_ID) b. SELECT * FROM STUDENT JOIN SCHOOL USING(S_ID) c. SELECT * FROM STUDENT NATURAL JOIN SCHOOL ON S_ID AND SCHOOL.SCHOOL_ID d. SELECT * FROM STUDENT JOIN SCHOOL ON STUDENT.S_ID = SCHOOL.SCHOOL_ID
Using MySQL, design a 2 table database. The data types of columns should be set properly tblMembers The tblMembers will be used to store the details of the Gym Members MemberID, Name, Surname, DateOfBirth, ID,Contact, DateJoined MemberType (Annual: R200/year, Monthly: R50/month) The tblPayments table will be used to keep track of payments made by Members. PaymentID, Date, Amount. The tblPayments should be related to tblMembers accordingly Using Java and the jdbc API , create a startup frame that will be used navigate the application. The frame should have 3 buttons. 1.4 The first button will open aa frame that can be used to add, update and delete Gyjm Members. The second button will open a frame that will be used to collect the payments made by students. 1.5 The third button will display a frame that calculates the current age and the balances, and displays a summary report in a table, as follows for an example: Order # is the sequence number of the member in tblMembers…
Consider a database table named "EMPLOYEES" with the following columns: E_EMPLOYEEID, E_FIRSTNAME , E_LASTNAME , E_DEPARTMENT and E_SALARY .Write SQL query to retrieve the first name, last names and salary of employees whose salaries are below $3000 and are part of the "House Keeping" department. Sort the results by the salary in descending order.
Q51: Which of the following tables will be the better candidate for Incremental Backup? • Customers • Products • Sales • Employees Q52: When normalizing tables and we say that attribute a determines attribute b we mean that : • When we type in a value for a, we can get multiple values for b • When we type in a value for a, we do not get any values for b • When we type in a value for a, we get one and only one value for b • Attribute a is the parent attribute and attribute b is the child attribute
Given the following relation that stores details of student registration: Stu_ID Name Town Province Course RegisteredDate S101 Malak Al Nadabi Al Khuwair Western ITDR2106 02-02-2020 S101 Malak Al Nadabi Al Khuwair Western ITDR1105 14-09-2019 S102 Nadar Al Hashli Daesit Southern ITDR1102 05-02-2020 S102 Nadar Al Hashli Daesit Southern ITDR1101 05-02-2020 S103 Basit Barkat Ruwi Central ITDR1105 06-02-2020 S104 Yeshan Al Khuwair Western ITDR2106 15-09-2019 If the functional dependencies are consistent with the above relation, put TRUE. If they are not, put FALSE. Stu_ID à Name, Town Town à Province Course à RegisteredDate RegisteredDate à Course Stu_ID, Course à RegisteredDate Stu_ID à Course Stu_ID

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