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2 - 2] 4 | Let S = 1 -1 1 The basis of S are 2 1 | O (2. 1, 1), (-2, 1, 2) O (2, 1, 1), (-4 .0. 1) O (2,1.1), (-2, -1, -1)

2 - 2] 4 | Let S = 1 -1 1 The basis of S are 2 1 | O (2. 1, 1), (-2, 1, 2) O (2, 1, 1), (-4 .0. 1) O (2,1.1), (-2, -1, -1)

Elementary Linear Algebra (MindTap Course List)
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter4: Vector Spaces
Section4.CR: Review Exercises
Problem 33CR: Determine whether S={1t,2t+3t2,t22t3,2+t3} is a basis for P3.
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2 2 - 2 4 | Let S =- 1 -1 1 The basis of S are 2 1 O (2. 1, 1). (-2, 1, 2) O (2, 1, 1), (-4, 0, 1) O (2.1.1). (-2, -1, -1)
Transcribed Image Text:2 2 - 2 4 | Let S =- 1 -1 1 The basis of S are 2 1 O (2. 1, 1). (-2, 1, 2) O (2, 1, 1), (-4, 0, 1) O (2.1.1). (-2, -1, -1)
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