EXP Find graphically, the convolution between x(6) and h(t) shown below. 2 -1 Axit 1 1 2 Sol- _y(t) = x(t) @ h(t). = x(t) @ [s(t) = S(t+1)] = X(t) S(t) = X(t) ⓇS (t+1) - = X(t) = x (t+1) = X(t) + [_x(t+1)] y(t) = A (t-1)-A(²+2) A: triangular pulse- h(t) x(t)@s(t)= X(t). -x (t+1) 44(0) How did he get the value inside the circle 2

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Your Question:
EXP Find graphically, the convolution between x(6)
and h(t) shown below.
2
-1
Axit
1
1
2
Sol-
_y(t) = x(t) @ h(t).
= x(t) @ [s(t) = S(t+1)]
= X(t) S(t) = X(t) ⓇS (t+1)
-
= X(t) = x (t+1)
= X(t) + [_x(t+1)]
y(t) = A (t-1)-A(²+2)
A: triangular pulse-
h(t)
x(t)@s(t)= X(t).
-x (t+1)
44(0)
How did he get the
value inside the circle
2
Transcribed Image Text:EXP Find graphically, the convolution between x(6) and h(t) shown below. 2 -1 Axit 1 1 2 Sol- _y(t) = x(t) @ h(t). = x(t) @ [s(t) = S(t+1)] = X(t) S(t) = X(t) ⓇS (t+1) - = X(t) = x (t+1) = X(t) + [_x(t+1)] y(t) = A (t-1)-A(²+2) A: triangular pulse- h(t) x(t)@s(t)= X(t). -x (t+1) 44(0) How did he get the value inside the circle 2
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