Consider the region R shown in the figurebelow and take note of the followingpoints of intersection:Point ofCurve 1Curve 2intersectiony = xy-axisoriginy = xy=x²-2 (2, 2)y = x²Y·2··1·↓-1··2 y-axisYR₁X|(0, -2)N2y = x^→ X- 2 y = x-1·|The definite integral that will give the areaof the region R using HORIZONTAL stripsis2² [(x² − 2) — x] dr2°C[x - (x² − 2)] dx2L [√y+2-y] dy02[₂√y +√y+2 dy + ²* [√y+2-y] dyAll of the aboveO None of the above

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Answered: -2 2 /y + 2 dy + √ ² [√y+2_y] dy

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Calculus

-2 2 /y + 2 dy + √ ² [√y+2_y] dy

Algebra: Structure And Method, Book 1

(REV)00th Edition

ISBN:9780395977224

Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Chapter9: Systems Of Linear Equations

Section9.1: The Graphing Method

Problem 24WE

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Question

Consider the region R shown in the figure
below and take note of the following
points of intersection:
Point of
Curve 1
Curve 2
intersection
y = x
y-axis
origin
y = x
y=x²-2 (2, 2)
y = x²
Y
·2·
·1·↓
-1··
2 y-axis
Y
R₁
X
|(0, -2)
N
2
y = x^
→ X
- 2

y = x
-1·|
The definite integral that will give the area
of the region R using HORIZONTAL strips
is
2
² [(x² − 2) — x] dr
2
°C
[x - (x² − 2)] dx
2
L [√y+2-y] dy
0
2
[₂√y +
√y+2 dy + ²* [√y+2-y] dy
All of the above
O None of the above

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