2 -2. f(x) = x³ (a) f(3) 3. g(t) = 21²-3t+1 (a) g(2)) 4. h(t) = √t+6-2 (a) h(-6)) (b) f(-2) (b) g(v) (b) h(3) (c) f(2b) (c) g(2-c) (c) h(x-6)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.3: Algebraic Expressions
Problem 32E
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In Exercises 1-8, evaluate the function at each specified value of the independent variable and simplify
2
2. f(x) = 3x³
(a) f(3)
3. g(t) = 2t²3t+1
(a) g(2))
4. h(t) = √t+6 − 2
(a) h(-6))
5. f(x) =
6. f(x) =
1
x² - 4
(a) f(2))
8.
3x + 5,
x²+2,
(a) f(-2))
X
7. f(x) = x²6
(a) f(x + 1))
x < -1
x>-1
8(x) = { x²-3₁ x5-1
x + 4,
x>-1
(a) g(-2))
(b) f(-2)
(b) g(v)
(b) h(3)
(b) f(x + 2)
(b) f(0)
(b) f(0)
(b) g(3)
(c) f(2b)
(c) g(2-c)
(c) h(x - 6)
(c) f(0)
(c) f(-1)
(c) ƒ(6)
(c) g(-4)
Transcribed Image Text:2 2. f(x) = 3x³ (a) f(3) 3. g(t) = 2t²3t+1 (a) g(2)) 4. h(t) = √t+6 − 2 (a) h(-6)) 5. f(x) = 6. f(x) = 1 x² - 4 (a) f(2)) 8. 3x + 5, x²+2, (a) f(-2)) X 7. f(x) = x²6 (a) f(x + 1)) x < -1 x>-1 8(x) = { x²-3₁ x5-1 x + 4, x>-1 (a) g(-2)) (b) f(-2) (b) g(v) (b) h(3) (b) f(x + 2) (b) f(0) (b) f(0) (b) g(3) (c) f(2b) (c) g(2-c) (c) h(x - 6) (c) f(0) (c) f(-1) (c) ƒ(6) (c) g(-4)
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