2- A simple wave wound de shunt motor has the following data: Armature resistance =0.1 ohm Shunt field resistance = 100 ohm Number of poles = 2 Number of conductors = 400 Mechanical and core loss at full load = 2000 W. When the motor is connected to a 400 Volt supply and is fully loaded it draws 104 A. Calculate at a speed of 3000 rpm: i) Armature current and E.M.F ii) Flux per pole iii) Copper losses within the machine.

2- A simple wave wound de shunt motor has the following data: Armature resistance =0.1 ohm Shunt field resistance = 100 ohm Number of poles = 2 Number of conductors = 400 Mechanical and core loss at full load = 2000 W. When the motor is connected to a 400 Volt supply and is fully loaded it draws 104 A. Calculate at a speed of 3000 rpm: i) Armature current and E.M.F ii) Flux per pole iii) Copper losses within the machine.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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A 4 pole 10V, DC shunt motor operates on a load current 10A, having wave connected armature with 200 conductors. The flux per Pole is 25 m Wb. Resistance of shunt field winding is 1 ohm and resistance of the armature is 0.15 ohm. a)What will be the factors to minimize the back emf?
A 4 pole10V, DC shunt motor operates on a load current 10A, having wave connected armature with 200 conductors. The flux per Pole is 25 m Wb. Resistance of shunt field winding is 1 ohm and resistance of the armature is 0.15 ohm. a) what would be the back emf?
D.C. Shunt generator runs at 400 rpm and delivers 500 KW to bus-bars having a constant voltage of 400V. Assuming the field excitation to be constant at 5A, Calculate the speed at which the generator must run if the load on it is to be reduced to 300KW. The armature resistance is 0.0150?
A 4 pole10V, DC shunt motor operates on a load current 10A, having wave connected armature with 200 conductors. The flux per Pole is 25 m Wb. Resistance of shunt field winding is 1 ohm and resistance of the armature is 0.15 ohm. d) Based on the back emf voltage value Eb= 10V, is it possible to be achievable this value? Give reason.
5. A DC shunt motor runs at 9oorpm from a 460V supply when taking an armature current of 25 A. Calculate the speed at which it will run from a 230V supply when taking an armature current of 15A. The resistance of the armature circuit is 0.8 Ω. Assume the flux produced per pole at 230V to have decreased to 75% of its value at 460V.
A 15 kW,230 V, short-shunt generator was run light as a motor to determine rotational losses at rated load. The applied voltage across the armature, computed for test was 254 V and the armature current is 2A. The armature, series field and shunt field resistances are 0.25Ω,0.25Ω and 100Ω, respectively. Calculate the generator efficiency at 75% load. Assume rotational losses to be constant.
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11. Armature copper loss of DC motor is constant with the load. Select one: True False
1- A 10kW, 200V, DC Shunt motor has 1-ohm armature resistance. At the starting of the motor, its back emf (Eb) is zero.Select one:TrueFalse 2- Identify which of the following loss is not varying with respect to load current? a.Iron loss b.Both Armature and Series field copper losses c.Series field Copper Loss d.Armature Copper Loss
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