2 (a) Six elements A, B, C, D, E, and F are pushed onto a stack in reverseorder, i.e., starting from F. The stack is popped five times and eachelement is inserted into a queue. Iv: e ements are deleted from thequeue and pushed back onto the stack. Now, one element is poppedfrom the stack. What is the popped element? Step by step justifkesyour answer.

import java.util.*; // importing required modulepublic class Main{ public static void main(String[]…

2 (a) Six elements A, B, C, D, E, and F are pushed onto a stack in reverse order, i.e., starting from F. The stack is popped five times and each element is inserted into a queue. IRv ements are deleted from the queue and pushed back onto the stack. Now, one element is popped from the stack. What is the popped element? Step by step justikes your answer.

2 (a) Six elements A, B, C, D, E, and F are pushed onto a stack in reverse order, i.e., starting from F. The stack is popped five times and each element is inserted into a queue. IRv ements are deleted from the queue and pushed back onto the stack. Now, one element is popped from the stack. What is the popped element? Step by step justikes your answer.

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter18: Stacks And Queues

Section: Chapter Questions

Problem 3PE

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Similar questions

(2) Answer the following questions concerning lists, stacks, and queues: Please be thorough with explanation! (b) Now consider implementing a stack as a class that relies on a vector, keeping track of the current size and capacity of the vector in the main object. You consider two possibilities. The first is to push (insert) to the beginning and pop (remove) from the beginning of the vector. The second is to push to the end and pop from the end of the vector. (Either way, if the vector is full and a push is applied, the vector will be resized to double its current capacity.) Is one of these possibilities better than the other? Briefly explain your answer.
Short answer: Answer the following in your own words: 1) Your friend says they implemented a stack as a linked list with reference pointers to both a head and the tail node (i.e. they implemented a stack as a double endedlinked list). They said this significantly improved the performance for all functions (push, pop, search, and update). Are they correct? Why or why not?
TRUE or FALSE? Answer the following question and state the reason why: A circular linked list has 2 node pointers. cout<<list.back()<<endl; = The back member function returns a reference to the last element in the list. In a Dynamic Stack, the pointer top stays at the head after a push operation. During a Pop operation in Static Stack, the elements are being moved one step up. In a dynamic implementation of stack, the pointer top has an initial value of null.
(2) Answer the following questions concerning lists, stacks, and queues Please be thorough with explanatio! (d) Suppose you are implementing a list of stacks. Let's say you decide to implement both the general list (the list of stacks) and each individual stack using a double linked list. Assume that there are currently N stacks in the list, and each stack has a maximum of K items, where N and K are both large. You are going to iterate through the general list and apply a single operation to each stack as you encounter it. Now answer the following four questions, using big-Theta notation: What is the average-case time complexity of pushing one additional item into each stack? What is the worst-case time complexity of pushing one additional item into each stack? What is the average-case time complexity of popping one item from each stack? What is the worst-case time complexity of popping one additional item from each stack? (For pops, if the stack is empty, you can assume that the pop…
Consider the following code segment , The variable q is an object of type Queue, the variable s is an object of type Stack. peek method looks at the first element in the queue without removing it. the remove method removes the first element from the queue. add method adds an element to the and of the queue or add an element to the top of the stack. pop method removes an element from the top of the stack What would be the content of the variable q (8 numbers) after we complete the second while loop in the code for (int i = 30; i <= 40; i ++) { if(i % 3 == 0) q.add(i); } while (!q.isEmpty()) { s.add(q.peek()); s.add(q.peek()); q.remove(); } while (!s.isEmpty()) { q.add(s.pop()); }
4.3 Refer to the code fragment below and convert the following Queue structure into a Stack structure. You should create a reference called S1 for the stack structure. Code: Queue Q1 = new LinkedList (); Q1.add("Sandra"); Q1.add (15); Q1.add (200); Q1.add ('#'); Q1. remove (); System.out.println(Q1); System.out.println(Q1.peek()); Q1.add("Mary"); System.out.println(Q1);
(2) Answer the following questions concerning lists, stacks, and queues: Please be thorough with explanation! (e) Suppose you are implementing a list of stacks. Let's say you decide to implement both the general list (the list of stacks) and each individual stack using a vector. Assume that there are currently N stacks in the list, and each stack has a maximum of K items, where N and K are both large. You are going to iterate through the general list and apply a single operation to each stack as you encounter it. Now answer the following four questions, using big-Theta: What is the average-case time complexity of pushing one additional item into each stack? What is the worst-case time complexity of pushing one additional item into each stack? What is the average-case time complexity of popping one item from each stack? What is the worst-case time complexity of popping one additional item from each stack? (For pops, if the stack is empty, you can assume that the pop itself is a…
Assume that stack and queue are MyStack and MyQueue objects, respectively. WhT are the contents of stack and queue after the execution of the following code fragment.
TRUE or FALSE? Answer the following question and state the reason why: cout<<list.back()<<endl; = The back member function returns a reference to the last element in the list. In a Dynamic Stack, the pointer top stays at the head after a push operation. During a Pop operation in Static Stack, the elements are being moved one step up. In a dynamic implementation of stack, the pointer top has an initial value of null.
10.7 Suppose you wish to reverse the order of elements of a queue. Usingonly Queue operations, describe how this would be done. (Hint: While you can’tuse a stack, you can use something similar.)10.8 Over time, the elements 1, 2, and 3 are pushed onto the stack, amongothers, in that order. What sequence(s) of popping the elements 1, 2 and 3 offthe stack are not possible?
Please be thorough with explanation (a) Consider implementing a stack as a class that relies on a singly linked list, maintaining pointers to both the start and end of the singly linked list in the main object. You consider two possibilities. The first is to push (insert) to the beginning and pop (remove) from the beginning of the linked list. The second is to push to the end and pop from the end of the linked list. Is one of these possibilities better than the other? Briefly explain your answer.
Short answer Answer the following in your own words: Your friend says they implemented a stack as a linked list with reference pointers to both a head and the tail node (i.e. they implemented a stack as a double ended linked list). They said this significantly improved the performance for all functions (push, pop, search, and update). Are they correct? Why or why not? Another friend implemented a queue as a linked list with only a head pointer (no tail node). She said this made performance of all functions (insert, remove, search, and update) categorically equal to a queue as a linked list with a head and a tail node. Is she correct? Why or why not?