2) Assume now that the glass used for the sides of the aquarium is different for the glass used for the bottom and consequently there is a difference in cost. If the glass for the sides is $3 per square ft and the glass for the bottom is $2 per square ft. The aquarium must hold 500 ft° of water. What are the dimensions of the aquarium that minimize the cost? a) Diagram (include variables) b) Objective function (state equation) : c) Constraints (state equation):_ d) Steps to the solution of the optimization problem using derivatives
2) Assume now that the glass used for the sides of the aquarium is different for the glass used for the bottom and consequently there is a difference in cost. If the glass for the sides is $3 per square ft and the glass for the bottom is $2 per square ft. The aquarium must hold 500 ft° of water. What are the dimensions of the aquarium that minimize the cost? a) Diagram (include variables) b) Objective function (state equation) : c) Constraints (state equation):_ d) Steps to the solution of the optimization problem using derivatives
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 17EQ
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