#+ )= 2 c(-)-2 sin (- 2 cos (#)-2 sin() 2 cas ()+32 sin () # + )F 2 ccs (2 sin () 27 (0) 27T +j2 sin( – 9. 27 2т (1) 4т + 9. - 27 2т (2) 10T -j2 sin 10T - 27 9. 2т (3) 16т -j2 sin 16т 9. 27 2n (4) 22т 22т + 27 2 cos -j2 sin( - 9. 27 27 #+ )F 2 cos ( 2 sin ( 27 (5 28T 28T - 9. 27 2т (6) 347 347 = 2 cos 27 -j2 sin 27 27 9. 2 (7)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.5: The Binomial Theorem
Problem 54E
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Question
Can you explain further how did the the values on blue are solved to get the values on red?
-256 – j256V3
Transcribed Image Text:-256 – j256V3
+ )=2 co(-)+;2 sin (-
2 cos () +62 sin ()
2 cos )j2 sin ()
(-끓 + n)) 2c따(뜰)t2sin()
(-+ ))F2 cos(#)+2sin()
2т (0)
9.
+j2 sin
27
2т (1)
27
9.
2т (2)
10л
10т
27
9.
2т (3)
16T
-j2 sin
16л
E 2 cos
9.
2т (4)
22т
22т
-j2 sin
9.
2т (5)
28п
28т
2 сos
-j2 sin(
27
9.
27
27
2 cas ()+32 sin (*)
2 cas ()j2 sin ()
)= 2 co- ()+32 sin ()
2т (6)
34т
34т
+
27
9.
2т (7)
40л
40т
27
2т (8
+
9
46т
46т
-j2 sin(
27
+
Transcribed Image Text:+ )=2 co(-)+;2 sin (- 2 cos () +62 sin () 2 cos )j2 sin () (-끓 + n)) 2c따(뜰)t2sin() (-+ ))F2 cos(#)+2sin() 2т (0) 9. +j2 sin 27 2т (1) 27 9. 2т (2) 10л 10т 27 9. 2т (3) 16T -j2 sin 16л E 2 cos 9. 2т (4) 22т 22т -j2 sin 9. 2т (5) 28п 28т 2 сos -j2 sin( 27 9. 27 27 2 cas ()+32 sin (*) 2 cas ()j2 sin () )= 2 co- ()+32 sin () 2т (6) 34т 34т + 27 9. 2т (7) 40л 40т 27 2т (8 + 9 46т 46т -j2 sin( 27 +
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