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2 Consider the matrix A = 1. Find the eigenvalues and eigenvectors of A. 2. Consider the polynomial p(r) = 5z2 – 6z. Compute p(A). 3. For the two eigenvectors computed in the first part of the problem, show explicitly that p(A)v = p(c)v, if c is the corresponding eigenvalue to v.

2 Consider the matrix A = 1. Find the eigenvalues and eigenvectors of A. 2. Consider the polynomial p(r) = 5z2 – 6z. Compute p(A). 3. For the two eigenvectors computed in the first part of the problem, show explicitly that p(A)v = p(c)v, if c is the corresponding eigenvalue to v.

Elementary Linear Algebra (MindTap Course List)
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.1: Eigenvalues And Eigenvectors
Problem 77E
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2 Consider the matrix A = 1. Find the eigenvalues and eigenvectors of A. 2. Consider the polynomial p(z) = 522 – 6x. Compute p(A). 3. For the two eigenvectors computed in the first part of the problem, show explicitly that p(A jv = p(c)v, if c is the corresponding eigenvalue to v. 4. Show that p(A)v = p(c)v holds in general, if v is an eigenvector of A for the eigenvalue c. 5. Assume now that v1, v2, ..., Vn are eigenvectors to different eigenvalues cı, C2, ..., Cn. We want to show that these eigenvectors are linearly indepdendent. To do so, write down a = 0 and show that all coefficient be are zero. To show, for example, that bị is zero, you can consider the polynomial P1(A)v. linear combination of the form v = bivi + byvgt... +bnUn P1 (2) = (r - c2)(z - c3)... (z - Cn) and evalutate
Transcribed Image Text:2 Consider the matrix A = 1. Find the eigenvalues and eigenvectors of A. 2. Consider the polynomial p(z) = 522 – 6x. Compute p(A). 3. For the two eigenvectors computed in the first part of the problem, show explicitly that p(A jv = p(c)v, if c is the corresponding eigenvalue to v. 4. Show that p(A)v = p(c)v holds in general, if v is an eigenvector of A for the eigenvalue c. 5. Assume now that v1, v2, ..., Vn are eigenvectors to different eigenvalues cı, C2, ..., Cn. We want to show that these eigenvectors are linearly indepdendent. To do so, write down a = 0 and show that all coefficient be are zero. To show, for example, that bị is zero, you can consider the polynomial P1(A)v. linear combination of the form v = bivi + byvgt... +bnUn P1 (2) = (r - c2)(z - c3)... (z - Cn) and evalutate
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