2 dx Nhere converas A dverge x(Inx Since undefned at =La dx him UE Inx hm du nt na P P+ PM dus dx lim Pr

Question

This question asks for what value(s) of p the improper integral converges and diverges. I am confused about how to determine convergence once I take the antiderivative because I no longer have a p value in the exponent to manipulate. Is my process thus far correct, and how do I find convergence of this function?