2 -dx Vx² + 2 1

Q: Evaluate:

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Q: 1 -dx 3-4х

A:

Q: 3. | (1- 2x) dx 0.

A: Given that, ∫01xdx=12 ∫01x2dx=13 ∫01x3dx=14 The integral to be evaluated is given as, I=∫011-2x3dx…

Q: 2-X 2-x-Y dza dx

A: the given integral is: ∫01∫02-x∫02-x-ydz dy dx we have to evaluate the given integral.

Q: 1 X-X -dx ах 3, -8 2vx

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Q: f(3x + 2)² dx

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Q: 8 3x -dx 3 3 V 2 – x 2 -

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Q: 9. f²-2x(3x - 1) dx

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Q: dy dx ³-√√3x² 2 √5x

A: We will solve the problem

Q: Ул4 — dx 2x2 + 1 3,

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Q: 1 Evaluate - dx (r+2)Vx2+4x

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Q: 1) f3x* dx +x dx 3) fxva² +I dx

A: We know that, ∫ xn dx = [( xn+1 )/( n+1 )] + C

Q: 4x x*e*dx (2sin dx V4-x2

A: We can solve all the intregration problems with tha mathod of substitution. In substitution we use a…

Q: 1. f4x-³ dx -3

A: Find the integral

Q: (2²–4)* -dx (x-2)²

A: We have to find the given integral

Q: (2х+3) dx (x2+3х-6)9

A: ∫2x+3(x2+3x-6)9dx=∫(x2+3x-6)-9 (2x+3) dxusing formula∫fn(x) f'(x)dx =fn+1(x)n+1+chere, f(x)=x2+3x-6…

Q: 2x5 – x3 + x +1 -dx - x(x² + 1)²

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Q: 4x² + 5 -dx 3

A: Given, integral is

Q: 2 sec2( sec-1x)dx xVx² -1 3. 3.

A: Here  we evaluate    ∫32 sec2sec-1xxx2-1  dx

Q: x + 3 -dx х — 1

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Q: | 2sin (x) dx = %3D

A: The answer is given below:

Q: 3-x Evaluate I = . -dx Vx-2°

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Q: 2x - 3 е 2 -dx,

A: As per our guidelines we only solve one question and rest of the question will be reposted.

Q: 4- у ду dx 2 ху +x = 0

A:

Q: x3 dx J4- x4

A: ∫x3dx4-9x4Multiply & divide by -36 =-136∫-36x3dx4-9x4since, ∫f'(x)f(x)dx= 2f(x)

Q: cosh 3x-1 S - dx 2

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Q: 11. f -dx 3x+1 +4x

A: these 2 questions are not related to each other so according to bartleby guidelines I need to solve…

Q: (2х-1)dx х4-2х3+x2

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Q: 2. 7ー dx - 2. 7-X 3

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Q: (x² + 4)³/2 -dx

A: Given integral is: I=∫x2+432xdx Integrating it: Put:u=x2+4dudx=xx2+4dx=x2+4xdu…

Q: 6. - 2х + 3) dx

A: According to Bartleby's guidelines we can solve only one question at a time. Apologise for the…

Q: (2² –4)* -dx (x–2)²

A: First we simplify numerator with using appropriate identities then integrate

Q: 2 Væ2 – 3 dx V3

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Q: ()* 3 -2 dx 7. dt 4

A: Solution 7: Given linear system is dxdt=3-24-1x Let A=3-24-1 Let the eigen value be λ So…

Q: 6 1 -dx /6 — х

A: solution:-∫2616-xdxusing substitution methodlet, 6-x=ux=2,  u=2x=6,  u=0-126-xdx=du

Q: 2 x -dx 6. Jo 1-x

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Q: 2x + 3 -dx. x2 + 3x + 4

A: To evaluate the integral: ∫2x+3x2+3x+4dx Evaluating the integral. Let substitute t=x2+3x+4…

Q: 2 | Vxe-*dx хе ах

A:

Q: (1-2х)2 dx 3.

A: Given :       ∫1 - 2x2x dx   To evaluate the given integral.

Q: 8. - dx V9-16x 8, 9–16x²

A: To integrate given equation.

Q: 6 x -dx („² + 1 ) (2x - 2)

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Q: /2 – x² dx. - 1 Væ2 + 1

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Q: 4x² + 5x³ – 3 ° - 3 dx X,

A: Answer is given below

Q: 2. 2x² + 4x-3 ,2 X dx

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: -1) 2. -dx (e² +1)

A: Given: - The indefinite integral is, ∫ex-1ex+1dx To find: - The solution of the given integral.

Q: x · 2-*dx

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Q: 2x +1 -dx J - 3x +2` 4. х — Зх

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Q: dx 2. x2 – 6x + 13 -4 dx 3. (x – 2)3

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Q: 3 2 - VX dx x² – 4 1 2]

A: ∫12xx2-43dxLet u=x2-4.=∫-3012u3du=12·∫-301u3du=1232u23-30=12--123· 323·32=-3-123· 3234

Q: 15. 1 dx V5x+4

A: