2 Find the average rate of change of g(x) = 6x³ + on the interval [-1, 1]. Enter your answer as either an integer or reduced fraction. > Next Question

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Math Problem: Average Rate of Change**

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**Problem Statement:**

Find the average rate of change of \( g(x) = 6x^3 + \frac{2}{x^4} \) on the interval \([-1, 1]\).

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**Instructions:**

Enter your answer as either an integer or reduced fraction.

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**Input Box:**

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**Navigation:**

\[ \rightarrow \text{Next Question} \]

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**Explanation of Average Rate of Change:**

To find the average rate of change of a function over an interval \([a, b]\), use the formula:

\[ \text{Average Rate of Change} = \frac{g(b) - g(a)}{b - a} \]

Here, \( g(x) = 6x^3 + \frac{2}{x^4} \), \( a = -1 \), and \( b = 1 \).

1. **Compute \( g(1) \):**
   \[ g(1) = 6(1)^3 + \frac{2}{(1)^4} = 6 + 2 = 8 \]

2. **Compute \( g(-1) \):**
   \[ g(-1) = 6(-1)^3 + \frac{2}{(-1)^4} = -6 + 2 = -4 \]

3. **Apply the formula:**
   \[ \text{Average Rate of Change} = \frac{g(1) - g(-1)}{1 - (-1)} = \frac{8 - (-4)}{1 - (-1)} = \frac{8 + 4}{1 + 1} = \frac{12}{2} = 6 \]

Therefore, the average rate of change of \( g(x) \) on the interval \([-1, 1]\) is \( 6 \).
Transcribed Image Text:**Math Problem: Average Rate of Change** --- **Problem Statement:** Find the average rate of change of \( g(x) = 6x^3 + \frac{2}{x^4} \) on the interval \([-1, 1]\). --- **Instructions:** Enter your answer as either an integer or reduced fraction. --- **Input Box:** | | |---| --- **Navigation:** \[ \rightarrow \text{Next Question} \] --- **Explanation of Average Rate of Change:** To find the average rate of change of a function over an interval \([a, b]\), use the formula: \[ \text{Average Rate of Change} = \frac{g(b) - g(a)}{b - a} \] Here, \( g(x) = 6x^3 + \frac{2}{x^4} \), \( a = -1 \), and \( b = 1 \). 1. **Compute \( g(1) \):** \[ g(1) = 6(1)^3 + \frac{2}{(1)^4} = 6 + 2 = 8 \] 2. **Compute \( g(-1) \):** \[ g(-1) = 6(-1)^3 + \frac{2}{(-1)^4} = -6 + 2 = -4 \] 3. **Apply the formula:** \[ \text{Average Rate of Change} = \frac{g(1) - g(-1)}{1 - (-1)} = \frac{8 - (-4)}{1 - (-1)} = \frac{8 + 4}{1 + 1} = \frac{12}{2} = 6 \] Therefore, the average rate of change of \( g(x) \) on the interval \([-1, 1]\) is \( 6 \).
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