2 Point P is equidistant from both [AB] and [AC]. Use congruence to show that P lies on the bisector of BAC. -B .P -C

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.1: Real Numbers
Problem 35E
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481
2
3
2 Point P is equidistant from both [AB] and [AC].
Use congruence to show that P lies on the
bisector of BÂC.
B
•P
Transcribed Image Text:481 2 3 2 Point P is equidistant from both [AB] and [AC]. Use congruence to show that P lies on the bisector of BÂC. B •P
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