√2 tan 0 + 2 sin 0 tan 0 = 0 (a) all degree solutions (Let k be any integer.) 0 = 360°k, 225° + 360°k, 315° + 360°k 0 = 360°k, 45° + 360°k, 45° +180°k O 0 = 0° +180°k, 225° + 360°k, 315° + 360°k 0 = 0° +180°k, 45° + 360°k, 45° + 180°k 8 = 180° + 360°k, 225° + 360°k, 315° + 360°k (b) 0 if 0° ≤ 0 < 360° e = 0°, 225°, 315°, 405° x Read It Watch It Need Help? (Enter your answers as a comma-separated list.)

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