2) y=-(x+2)²+ 1

Q: 8- (y – y) dy

A:

Q: What will be our X1 if X2= -2, y1= 5, y2= 3 and our distance is 15?

A:

Q: ² = 3x² + 3y², x = 0, y = 0, z = 2

A: Solution

Q: 1. (1 - x)y' = y?

A:

Q: 17. y"-5y6y=t² + 7, y(0) = 1, y'(0) = 0

A: For an initial value problem with boundary conditions available, we have to convert the given…

Q: 2. Find Y if y =x +3x-7 and x 21 +1.

A: Given: y=x2+3x-7x=2t+1

Q: Find y' and y". In(2x) y = 1- In(32) y' y"

A: The given function y = ln(2x)/(x^5):   Find the first derivative of the function y = ln(2x)/(x^5)…

Q: 2 Consider the hypocycloid with equation y 3 +x3 =73 2 2

A:

Q: 3- If √secx + 5cosx find y

A:

Q: 3 1) y=--x-1 2 A) B) C) D)

A:

Q: Find ƒx (x, y)  and ƒy( x, y) .

A: Differentiate the function f(x,y)=ln|2x2+y2| with respect to x and keeping y as constant and carry…

Q: 3. zy if y + x² – 3xz = 222

A:

Q: - / 4(1-)esc2(1– y)dy

A:

Q: nclosed by x = y, x = 2 - y and the x-axis?

A: And: 5/6

Q: 2. у"- Зу'+ 2у-е" when y(0)%3D1 аnd y'(0) —0 3t

A:

Q: a) Lin 5) x2+2y2

A:

Q: 18. y = -- 2x - 4 7x +y 2 19. y = x + 6x x-y= 4 20. y = x + 4r – 15 y 25 x

A:

Q: = Express by ¡y¡ in the terms of x variables where y; = C₁jx; and bicik = 8%.

A: express bijyiyj in the terms of x variables where yi=cijxj             ...i and bijcik=δik…

Q: Assume that x² + y² = 4xy. Then y' Select one: True False 2x-4 4+3y²*

A: Let's solve derivative of function  and maximum value of given function.

Q: ý +4ý + 3y Y6) = y'(0) = 1 %3D to

A: Given that

Q: 7) y"+4y+20y-23sint-15cost y(0)-0, y'(0)--1

A: We have to solve given problem:

Q: Qil If y , Show that y=2x- 2y3

A:

Q: 9) If y = 3x +x² - 5 and z = x2 - 12, find 2(y +z).

A:

Q: Suppose that W (y1, Y2) (t) = 4, and y3 Yı – 3y2. What is W (y1, Y3) (t)?

A: Correct option -12 We have to find out the value for Wy1,y3t.

Q: 3メ+2y-Z=1 メ-ツ+らる-2 2X +y =3

A:

Q: у" + Зу" + Зуy' + у %3D 30 е -х

A:

Q: 2, y(t) = 4t – 6 y(t) = t - 5 5, y(t) = 4t (t) = 4t – 5

A: We have to choose the correct answer

Q: 2) Find of y = क सम्माय 2) r*+1)(2x+3)

A: Simplify the given expression and take log on both sides.…

Q: b) y = In(xeVx + 2)

A: The solution are next step..

Q: .What is the set of points given by (a) x² + 2xy + y² = 1 (b) x² + y² - 2x + 4y + 5 = 0?

A: To find the set of points satisfying the given relation.

Q: *5. Consider ry² + x°y = 6.

A: We have to find the derivative

Q: Eliminate the arbitrary constants of  y=e^(-3x) (Acos5x - Bsin5x) + Cx Where A, B,  and C are the…

A: It is given that, y=e-3x(Acos5x-Bsin5x)+Cx. Obtain the first derivative as follows:…

Q: у" + 16у %3D0, yT4) -2y' (π/4) -1 =

A:

Q: у' %— х — 4у, when x %3D 2,у 3 3 y' — х — 2усot 2x

A:

Q: [a] -(-x)= x [b] (-x)y = -(xy) and (-xX- y)= xy

A: We use The fact that (-x)+x=0 and x*0=0

Q: 40 mz 0XT = mz TYÖ = Y mz X0Y =

A:

Q: π 9- y² dy y 2 π 6.

A:

Q: Solve y"+y' + y = 6sin (2x) supo

A:

Q: 1. y+ /x + y = 2x at ( 2, 2)

A: Follow the procedure given below.

Q: 32. In y = 2y² - x; (2, 1)

A:

Q: 1. y 2x + 4x at point (-2,0)

A:

Q: у4у? -16у +19 dy (y-2)°

A: This indefinite integral can be solved by the substitution method.

Q: 2 – 2ay) dy,

A:

Q: In x y of y = 3

A: Find your answer below

Q: 2 lim y→7L_– 4y – 21 3y Зу — 17у — 28 -

A:

Q: 3. (4, 6) and (0, -2) Y2 m X,- X,

A: we have to find m

Q: b) Show that Δ2y0 = y2-2y1 + y0.

A: We have to show that Δ2y0 = y2-2y1 + y0.

Q: 2) If Ø(x. y. z) = 3x²y – y³z² , then VØ

A:

Q: Eliminate the arbitrary conutantu 2. %3D y= ax + be

A: