2. (1.5) Calcular el torque producido por la tensión T = 20 N en el punto 0. 1.2 m- 0.7 m 1.6 m 30° 0.8 m T B -X
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- Help ASAP! F: 795 N, d: 0.90 m, e: 1.85 m, f: 1.95 mIn machine design we usually compare the equivalent stress of the component with the: a) Allowable stress b) Machine stress c) Force d) Moment e) TorqueGears b and c have diameters of 10 cm and 4 cm, respectively. The maximum shear stress supported by the bars is 550 kgf/cm^2 and the material from which they are manufactured has a shear modulus G = 8x10^5 kgf/cm^2. Determine: The diameter of each bar, such that the maximum shear stress is not exceeded. The torsional rotation of point d. T = 12 Ton-m
- The three-bar truss in Fig. a is subjected to a horizontal force of 5 kip. If the cross-sectional area of each member is 0.20 in2, determine the horizontal displacement at point B. E = 29(103) ksi.A thinwalled, filamentwound pressure vessel is pressurized such that at a point in the wall is in the figure below. ?=[ ????????0 (c)the magnitude of the normal stress acting on the filaments, and (d)the magnitude of the shear stress (b)the magnitude of the traction vector acting alongthe direction of the filament winding. −????????0 Determine: ] suitable stress tensor ?′for a rotated coordinate axis. (You can use Matlab or a calculator to The filament winding angle is ?=53.13°from the longitudinal axis ofthe pressure vesseas shown Noting that the transformation matrix to rotate the x-y coordinate system anticlockwise by ?is: (e)find the magnitude of the normal stress and shear stress acting on the filaments by finding a (a)Write down the stress tensor in the xyzcoordinate system. under a plane-stress state with ???=10.946MPa, ???=21.892MPaand ???=0MPa. 001 perform the tensor multiplications)Consider a uniform ladder of length 4.3 m and mass 10 kg. The ladder is falling over, pivoting about the end that is touching the ground. Someone is pushing on the top end of the ladder with a horizontal force of size 415 N. At the instant when the ladder makes a 46 degree angle with the horizontal, calculate the net torque on the ladder about its bottom end, in N m. Make your answer positive, and use g = 10 m/s2. (Please answer to the fourth decimal place - i.e 14.3225)
- Answer no. 17. Derive with the formula below, show the cancellation, explain the step by step and DRAW a free body diagram/figure. refer with this: PE1 + KE1 + U1 + WF1 + Q1 + W1 = PE2 + KE2 + U2 + WF2 + Q2 + W2 + E losses.A Solid shaft transmits 600 N.m torque. If the maximum shear stress induced in the shaft is 50 N/mm2, the minimum diameter of the shaft isThe mechanism of four rods (Rocker Crank) as shown in the picture below is O2A=15cm long, AB = 40 cm, BD = 10 cm, O2O4 = 45 cm, and 04B = 30 cm. Bar 4 receives a force Q of 4000 N. Determine the magnitude and direction of the torque in rod 2.
- 5 - note: ignore weight of the bar.A) ( - 6/7)T(CB) + A(y)=0 (A=reaction force at A, A(x), A(y), A(z) are components of force A)B) (2/7)T(CB)+A(x)=392 (A=reaction force at A, A(x), A(y), A(z) are components of force A)C) A(x)=2A(y) (A=reaction force at A, A(x), A(y), A(z) are components of force A)D) A(x)=5A(z) (A=reaction force at A,A(x), A(y), A(z) are components of force A)Under non-uniform and slippery road conditions, two forces (u and w), shown in the figure (image 1), are performed on the truck's rear wheels, which have a limited slip rear differential. Choose the alternatives that are true: (data: u = 92lbf and w =57lbf) (obs1.0: 1''= 1 in = 25,4mm) (obs2.0: 1lbf = 4,448N) a) the force vector resulting from the two forces is -149i [lbf] b) the resultant of the two forces has an intensity equal to 149lbf c) the ordinate of the point of intersection of the line of action of the resultant of this system of forces with the y axis is 7.05in d) adopting the counterclockwise direction as positive, the total moment of the two forces in relation to point g is equal to -1050lbf.in e) the total moment vector in relation to the G point is equal to -1050i [lbf.in]A rectangular steel block is 3 inches long in the x direction, 2 inches long in the y direction, and 4 inches long in the z direction. The block is subjected to a triaxial loding if three uniformly distributed forces as follows: 48 kips tension in the x direction, 60 kips compression in the y direction, and 54 kips tension in z direction. If v=0.30 and E=29x10^6 psi, determine the single uniformly distributed load in the x direction that would produce the same deformation in the y direction as the original loading. DetermineNormal strain in x, y & z direction.Elongation in x, y & z direction.