2. A survey found that out of 900 workers, 150 said that they were interrupted by frank phone calls. Find the 95% confidence interval of the population proportion of workers who are interrupted by these calls.
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- The molecular weight of a particular polymer should fall between 750 and 1,035. Thirty samples of this material were analyzed with the results X-bar = 902 and s = 90. Assume that molecular weight is normally distributed.imagine a large class where nearly everyone scores between 83.84%, with hardly any dispersion beyond this narrow range (so it would appear to have a very narrow peak). How would your describe this distribution of data in terms of kurtosis?The compressive strength of concrete is normally distributed with mean 2500 psi and standard 50 psi. Find the probability that a random sample of n=5 specimens will have a sample mean diameter that falls in the interval from 2499 psi to 2510 psi. Answers in 4 significant figures.
- Later, when the medical devices are in full production, a consultant advised that the breaking strength of these devices should not be less than 5.5 psi (pounds per square inch) on average. In the latest batch produced, a technician has noticed a visual defect that may affect the breaking strength of the devices. To investigate, a sample of 8 devices are randomly selected from the batch and the pressure at which they break are recorded as : 6.6, 7.7, 8.0, 6.3, 6.1, 6.3, 6.3, 6.1 these are summarized as having an average breaking strength of 6.68 psi and a standard deviation of s = 0.75 psi. Test, at significance level α = 0.05, whether there is evidence that the average breaking strength of the batch of devices is less than the required breaking strength, by testing the hypotheses: H 0: μ = 5.5 psi H a: μ < 5.5 psi. An estimate of the population mean is . The standard error is . The distribution is (examples: normal / t12 / chisquare4 / F5,6). The test statistic has value TS=…A random sample of 25 tires gave the average life as 38000 km and S.D. as 5000 km. Can it be concluded that the sample is drawn from a population with a mean life of 40000 km?(a) Calculate a 95% two-sided CI for the true average bond strength. (b) Calculate a 95% two-sided CI for the proportion of all such bonds whosestrength values would exceed 10. show major intermediate steps.
- In response to concerns about nutritional contents of fast foods, McDonald’s announced that it would use a new cooking oil for its french fries that would decrease substantially trans fatty acid levels and increase the amount of more beneficial poly-unsaturated fat. The company claimed that 97 out of 100 people cannot detect a difference in taste between the new and old oils. Assuming that this figure is correct (as a long-run proportion). Let X denote the number of individuals who can taste the difference between the two oils in a random sample of 1000 individuals who have purchased fries at McDonald’s. If it turns out that 65 individuals in the sample can taste the difference between the two oils, would you question McDonald’s claim? Explain why or why not.In response to concerns about nutritional contents of fast foods, McDonald’s announced that it would use a new cooking oil for its french fries that would decrease substantially trans fatty acid levels and increase the amount of more beneficial poly-unsaturated fat. The company claimed that 97 out of 100 people cannot detect a difference in taste between the new and old oils. Assuming that this figure is correct (as a long-run proportion). Let X denote the number of individuals who can taste the difference between the two oils in a random sample of 1000 individuals who have purchased fries at McDonald’s Find the Distribution of X.Assume that the helium porosity (in percentage) of coal samples taken from anyparticular seam is normally distributed with true population variance 0.36.(a) Compute a 95% two-sided CI for the true average porosity of a certain seam if the average porosity for 20 specimens from the seam was 4.85. (b) How large a sample size is necessary if the width of the 95% two-sided CI is to be 0.5? (c) Compute a 98% upper one-sided CI for true average porosity of another seam based on 16 specimens with a sample average porosity of 4.56.show major intermediate steps.
- In response to concerns about the nutritional contents of fast foods, McDonald’s announced that it would use new cooking oil for its french fries that would decrease substantially trans fatty acid levels and increase the amount of more beneficial poly-unsaturated fat. The company claimed that 97 out of 100 people cannot detect a difference in taste between the new and old oils. Assuming that this figure is correct (as a long-run proportion). Let X denote the number of individuals who can taste the difference between the two oils in a random sample of 1000 individuals who have purchased fries at McDonald’s. Use the normal approximation with continuity correction to find the probability that at most 5% can taste the difference between the two oils.A sample of 130 is drawn from a population with a proportion equal to 0.67 **Round to four decimal places as needed**Cal Poly Pomona found that 15% of its students withdraw without completing Calculus I course. Assume that 30 students registered for the course. Can we use normal approximation method to calculate #3? .
