2. An unsymmetrical parabolic curve has a forward tangent of +8% and a back tangent of -5%. The length of the curve on the left side is 60m, what is the elevation of the highest point on the curve if the vertex is at station 10+200 of elevation 100m? (Disregard this and solve the amended problem on No.3)

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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2. An unsymmetrical parabolic curve has a forward
tangent of +8% and a back tangent of -5%. The length of
the curve on the left side is 60m, what is the elevation of
the highest point on the curve if the vertex is at station
10+200 of elevation 100m? (Disregard this and solve the
amended problem on No.3)
3. An unsymmetrical parabolic curve has a forward
tangent grade of +8% and a back tangent grade of -5%.
The length of the curve on the left side of the tangents
intersection is 100 meters long while on its right side is
150 meters long. The tangents intersection is located at
station 10 + 200 having an elevation of 100 m. Determine
(a) location and elevation of the lowest point on the curve
and (b) the elevation of station 10+300.
Transcribed Image Text:2. An unsymmetrical parabolic curve has a forward tangent of +8% and a back tangent of -5%. The length of the curve on the left side is 60m, what is the elevation of the highest point on the curve if the vertex is at station 10+200 of elevation 100m? (Disregard this and solve the amended problem on No.3) 3. An unsymmetrical parabolic curve has a forward tangent grade of +8% and a back tangent grade of -5%. The length of the curve on the left side of the tangents intersection is 100 meters long while on its right side is 150 meters long. The tangents intersection is located at station 10 + 200 having an elevation of 100 m. Determine (a) location and elevation of the lowest point on the curve and (b) the elevation of station 10+300.
1. A symmetrical parabolic curve has descending grade of
6% and an ascending grade
120.25 whose elevation is at 14.375 m. The two grades
are to be connected by a parabolic curve, 160 m long. Find
the elevation of the first quarter and lowest points on the
2% and intersect at Sta 5 +
curve.
80
80
40
PCa
1* quarter point
-6%
www
+2%
. Lowest point
Elev 14.375
SQ
0.02
go
0.06
0.02
Grade Diagram
S1
S2
Transcribed Image Text:1. A symmetrical parabolic curve has descending grade of 6% and an ascending grade 120.25 whose elevation is at 14.375 m. The two grades are to be connected by a parabolic curve, 160 m long. Find the elevation of the first quarter and lowest points on the 2% and intersect at Sta 5 + curve. 80 80 40 PCa 1* quarter point -6% www +2% . Lowest point Elev 14.375 SQ 0.02 go 0.06 0.02 Grade Diagram S1 S2
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