2. Consider the alternating series 1 –+-+..., i.e. Eak where az = (-1)k-1 for all k e N. 4 Let Sn =E- ak denote the partial sums. (a) Show that Eak is not absolutely convergent. (b) Show that for all n E N, 1 San =E 1 = S2n + and S2n+1 2k(2k – 1) 2n + 1 k=1 (Hint: group pairs of odd and even terms.) (c) Prove that the sequence of even partial sums (S2n) has a limit S. (d) Prove that the whole sequence (Sm) has the same limit S, and hence , ak = S.

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter8: Sequences And Series
Section8.3: Geometric Sequences
Problem 4E: (a) The nth partial sum of a geometric sequence an=arn1 is given by Sn=. (b) The series...
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2. Consider the alternating series 1 –+-+.
i.e. Ear where ar = (-1)k-1! for all k e N.
Let Sn
E- ak denote the partial sums.
(a) Show that ak is not absolutely convergent.
(b) Show that for all n E N,
n
1
S2n
and S2n+1
1
= S2n +
2 2k(2k – 1)
2n + 1
k=1
(Hint: group pairs of odd and even terms.)
(c) Prove that the sequence of even partial sums (S2n) has a limit S.
(d) Prove that the whole sequence (Sm) has the same limit S, and hence E, ak = S.
Transcribed Image Text:2. Consider the alternating series 1 –+-+. i.e. Ear where ar = (-1)k-1! for all k e N. Let Sn E- ak denote the partial sums. (a) Show that ak is not absolutely convergent. (b) Show that for all n E N, n 1 S2n and S2n+1 1 = S2n + 2 2k(2k – 1) 2n + 1 k=1 (Hint: group pairs of odd and even terms.) (c) Prove that the sequence of even partial sums (S2n) has a limit S. (d) Prove that the whole sequence (Sm) has the same limit S, and hence E, ak = S.
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