a. How many subnets are there in this network? b. What are the first valid host and last valid host of 4th Subnet?
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A: Note:-As per policy, I can be entitled to answer only the first three questions. Wired network:…
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A: Intro: This is a concept which comes under subnetting in Networking.
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A: The required answer is
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Q: How many subnets and maximum hosts per subnet can we get from the subnet network 172.27.0.0/23?
A: I'm providing the answer to the above question. I hope this will be helpful for you...
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A: Introduction :
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A: I'm providing the answer of above question. I hope this will be helpful for you.
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A: Solution is:-
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Q: o. What are the first valid host and last valid host of 4th Subnet?
A: The answer is
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- THINKING CRITICALLY Which of the following hosts on a corporate intranet are on the same subnet? a. b. c. d.Consider the IP address : 157.110.88.0. We need 30 subnets in such a way that each subnet may host up to 64 hosts. i) This address is of which type? ii) How many bits will be required for subnet ID? iii) How many usable subnets will be there? iv) What will be the subnet mask? v) What will be the address of 47th host of 25th subnet?Given 192.168.31.0 a. How many bits are in the host field for this network? _ b. If we need to set up 30 subnets, how many bits must be used for subnetting? _ c. How many bits are left over that can be used for host addresses? _ d. How many subnets can we create from this? _ total subnet? usable subnet? e. How many hosts could be assigned on each subnet? _ total possible host? Usable hosts? f. What subnet mask will be used? _g. What is the network address for this entire network? _ h. What is the broadcash address for this entire network? _ Show Solution
- Given the Class A network: 125.0.0.0 a. How many bits are in the host field for this network? ________b. If we want to set up subnets to allow up to 200 hosts on each subnet, how many host bits must be used for host addressing? _____________c. How many bits are left over that can be used for subnetting? ____________d. How many subnets can we create from this? ________total subnets _____ usable subnetse. How many hosts could be assigned on each subnet?________total possible hosts ______ usable hostsf. What subnet mask will be used? _______________________g. Complete the following table for the first 4 subnets in this network. Give the subnet number (starting from 0), subnet address, host address range, subnet broadcast address, and identify which subnets are assignable (usable) and which subnets are not assignable.Given the Class B network: 185.85.0.0 a. How many bits are in the host field for this network? ________b. If we want to set up subnets to allow up to 100 hosts on each subnet, how many host bits must be used for host addressing? _____________c. How many bits are left over that can be used for subnetting? _____________d. How many subnets can we create from this? ____total subnets ____ usable subnetse. How many hosts could be assigned on each subnet?________ total hosts ______ usable hostsYou are assigned a network address 132.27.120.0/27. You want to create 2 subnets. For each subset, please give the network address, broadcast address, the lowest IP address, and the highest IP address for hosts? All the addresses should be in this format: x.x.x.x/x
- Suppose an ISP owns the block of addresses of the form 126.120.40.64/26. Suppose it wants to create four subnets from this block, with each block having the same number of IP addresses. Now answer the following: a. What is the maximum number hosts each subnetwork can have? b. What are the subnet addresses (of form a.b.c.d/x) for the four subnets? c. What is the first usable IP address of first subnet? d. What is the broadcast address of first subnet? e. What is the last usable IP address of first subnet?Question 2 Consider a network of Class C with network address 200.1.1.0 a. How many total IP addresses are there in this network? b. How many maximum hosts this network can have? c. What is the IP address that can be assigned to Host 1? d. What is the Broadcast IP address for this network?Given an IP address 94.0.0.0/20, answer the following questions: I. What is the IP address class? II. Netid and hosted? III. Number of bits borrows? IV. Number of total subnets created? V. Number of bits left? VI. Number of host per subnet? VII. Total of host for all subnets? VIII. The new subnet mask? (after subnetting) IX. Show the subnet address, host range and broadcast address of the first and the last block of the subnet created.
- Class b network: 130.30.0.0 a. How many bits are in the host field for this network?b. If we want to set up subnets to allow up to 200 hosts on each subnet, how many host bits must be used for host addressing?c. How many bits are left over that can be used for subnetting?d. How many subnets can we create from this? total subnet? usable subnet? e. How many hosts could be assigned on each subnets? total possible hosts? usable hosts?f. What subnet mask will be used?60- A network for a local office requires 4 LAN subnets as follows: · Subnet A - North Office with 31 hosts; · Subnet B - East Office with 15 hosts; and · Subnet C - South Office with 7 hosts. · Subnet D – West Office with 4 hosts. Given the IP Address 192.168.15.0 /24 and above described network requirements: 1. Design an optimal address scheme using Variable Length Subnet Mask (VLSM) method; What will be the range of usable (assignable) host addresses in Subnet D? Select one: A. 192.168.15.224 to 192.168.15.255 B. 192.168.15.113 to 192.168.15.118 C. 192.168.15.192 to 192.168.15.254 D. 192.168.15.193 to 192.168.15.240 E. 192.168.15.192 to 192.168.15.23951- A network for a local office requires 4 LAN subnets as follows: · Subnet A - North Office with 31 hosts; · Subnet B - East Office with 15 hosts; and · Subnet C - South Office with 7 hosts. · Subnet D – West Office with 4 hosts. Given the IP Address 192.168.15.0 /24 and above described network requirements: 1. Design an optimal address scheme using Variable Length Subnet Mask (VLSM) method; and What will be the network address of Subnet A? Select one: A. 192.168.15.0 B. 192.168.15.32 C. 192.16.15.128 D. 192.168.15.1