2. Consider the function Se=1/x f(x) = { 0 x>0 x ≤0. Graph/sketch this function. Show that this function satisfies f(n) (0) 0 for all n ≥ 0 so its Taylor series must be 0+0·x+0·x² + ... = 0. Why is f itself is not equal to its Taylor series? ∞ (1) =
2. Consider the function Se=1/x f(x) = { 0 x>0 x ≤0. Graph/sketch this function. Show that this function satisfies f(n) (0) 0 for all n ≥ 0 so its Taylor series must be 0+0·x+0·x² + ... = 0. Why is f itself is not equal to its Taylor series? ∞ (1) =
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.1: Equations
Problem 62E
Related questions
Question
![2. Consider the function
Se=1/x
f(x) = {
0
x>0
x ≤0.
Graph/sketch this function. Show that this function satisfies f(n) (0)
0 for all
n ≥ 0 so its Taylor series must be 0+0·x+0·x² + ... = 0. Why is f itself is
not equal to its Taylor series?
∞
(1)
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3688a312-1b6e-40d4-973f-537807921925%2Fe7d2cbde-9bc4-4f3d-9cbe-66b439f13407%2F9z43tlt_processed.png&w=3840&q=75)
Transcribed Image Text:2. Consider the function
Se=1/x
f(x) = {
0
x>0
x ≤0.
Graph/sketch this function. Show that this function satisfies f(n) (0)
0 for all
n ≥ 0 so its Taylor series must be 0+0·x+0·x² + ... = 0. Why is f itself is
not equal to its Taylor series?
∞
(1)
=
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