2. (D² + 8D + 16)y = 1-e4x

Q: Q4. Find the values of the constants a, b, c so that - F = (axy + bz³)ī+ (3x² − cz)j + (3xz² − y)k…

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Q: Find fx, fy, Tz (3x2 + y2 + 2z²) f(x,y,z) = e - fx=

A: f =e-3x2-y2-2z2  For fx ,we take y and z as constant and x as variable.  fx=∂f∂x For fy , we take x…

Q: B. ty" – (t+ 1)y' +y = t?

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Q: Use variation of parameters plem) to find a particular solution to y" – 2y' – 15y = e -3t %3D You do…

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Q: (D²+1) y 4 see X . ニ

A: 1. We know, ∫secnxdx=n-2n-1∫secn-2xdx+secn-2xtanxn-1   Given differential equation,…

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Q: 4-у2 r2x+y dzdædy -V4-y2 Jo

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Q: e the following nth-order equation using the variation of parameter method: y"-3y"+3y'-y=

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Q: 5. Exact Difle rential Equation: 3ry -4y' +6dr + (r° – 6x°y² - 1kty =0

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Q: X2 , 1 avuu. 3 VA 3. x = y3, 0 sy s1 about y-axis.

A: Given function is x=y^3

Q: B. ty – (t+ 1)y + y = t²

A: Solve using variation of parameters :               ty''-t+1y'+y=t2            -------- (1)…

Q: se the method of variation of parameters to determine a particular solution to the given equation.…

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Q: r/64–x² r61-x²-y² x dz dy dx -67+x²+y²

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Q: cx + dy - f(x, y) = ; P(3, 4); u =i+ x - y

A: Given that  f(x,y)=(cx+dy)/(x-y) P(3,4) and u=(4/5,3/5) To find the directional derivative of f at p

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Q: Use variation of parameters to find a particular solution of y"- 2y' + y = 14xie Yp(x) =

A: Auxiliary equation for the given equation:

Q: Obtain the particular solution 1. (D³ +6D² + 12D + 8)y=0 when x = 0, y = 1, y'= -2, y" = 2 2. y" +…

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Q: 2. b. Then, use the linearization to approximate the number V8.7. Be sure to show work, and clearly…

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Q: [Q4] Applying the method of variation of parameters, solve x'y" - 2xy'+2 y = x' sin x

A: The solution is given as

Q: Using the variation of parameters, find the particular solution of (D2 +1)y = secx

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Q: Use variation of parameters to find the particular solution to y'' + 5y' + 4y = 2e-34 Y(t) = […

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Q: SOLVE THE EQUATION (y -2) dx - (x-y-Ddy = o ISSING THE DE LINEAR IN x 4 Y VAKIABLES.

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Q: Solve using variation of parameters y" – y = e2=

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Q: If variation of parameters method is used when solving the equation y 1 then what is the v3 (x) of…

A: find the particular solution as following way:-

Q: he equilibrium pul 12) P(x) = -2x + 8, S(x) = 3x + 2 %3D

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Q: 1. (D 2 + 3D + 2)y = 4t 2 By: (a) reduction of order, and (b) variation of parameters.

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Q: Exercise 5 Using the method of variation of parameters, the particular solution , for y"+3 + 2y = "…

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Q: REDUCTION OF ORDER AND VARIATION OF PARAMETERS 1. (D² + 4) y = tan 2x 2. (D² + 8D + 16)y = C. 1-e4x

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Q: Find the value of d2y/dx2 at the point defined by the given value of t. x = t, y = square root 2t ,…

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Q: Particular solution of y' = x+xy²/4y, y(1) = 0

A: Given differential equation- y'=x+xy24y   , y(1)=0 We need to find particular solution of the given…

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A: The given differential equation is…

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A: Revenue function is given R(x,y) = 19+162x+210y-3x2-5y2-6xy  , it is function of two variable…

Q: Using the variation of parameters, find the particular solution of (D2+1)y=secx

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Q: (D² - 4D + 4)y= e2x sec²x

A: Reduction of order and variation of parameter (D^2-4D+4)y=e^(2x)sec^x

Q: Using the method of Variation of Parameters, the particular solution y, for the NHLDE y"+y=sec x j5…

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Q: The Method of Variation of Parameters (3) y" + 4y = sec x

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Q: V4 – a2 - x2 valuate f, S Sva-a - ° ( + 2²) kz dz dy dæ – a2 – 3y? (y + z2) kz dz dy dx

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Q: Solve for general solution using the variation of parameter method x²y" – 2xy' + 2y = xFe* find the…

A: Given DE is x2y''-2xy'+2y=x5ex. Use the variation of parameters method to solve the DE.

Q: Solve using variation of parameters: y" – 2y' + y = -

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Q: General solution of dy = 4x+xy² Present your answer in the form /(1 – x²)(4 + y²). Avoid dx y-x²y…

A: As per our guidelines, we are supposed to solve only first question. Kindly repost other question as…

Q: (D² – 4)y = 2 – 8x; when x = 0, y = 0, y' = 5. %3D ANS. y = e2x – e-2* + 2x – }.

A: We have to find solution of given differential equation.

Q: Q4. Find the values of the constants a, b, c so that - - F = (axy + bz³)i + (3x² − cz)j + (3xz² –…

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Q: y = (2x + 1)v2x+1

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