2. Define sequences (an) and (bn) by letting an-1+ bn-1 an = bn = Van-1bn-1- Deduce from the previous part that an > bn for all n, and hence also that an > an+1 and bn+1 > bn for all n.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterA: Appendix
SectionA.3: Inequalities
Problem 6E
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I need help with 2.

In #1 I already established that a1>b1

I just don’t know ho to elaborate for 2

Let ao
and bo be two positive real numbers with ao > bo. The arithmetic mean of ao and bo is
ao + bo
2
and the geometric mean of ao and bo is
b1 = Vaobo.
1. For any values of ao and bo, show that a1 > b1. This is a special case of the arithmetic mean - geometric
mean (AMGM) inequality which says that the same inequality holds for the arithmetic and geometric mean
of more than two numbers (you don't need to prove this more general fact). Hint: start with the fact that
(ao – bo)2 > 0.
2. Define sequences (an) and (bn) by letting
An-1+ bn-1
An
an-1bn-1.
Deduce from the previous part
that
An > bn
for all n, and hence also that
An > an+1 and bn+1 > bn
for all n.
Transcribed Image Text:Let ao and bo be two positive real numbers with ao > bo. The arithmetic mean of ao and bo is ao + bo 2 and the geometric mean of ao and bo is b1 = Vaobo. 1. For any values of ao and bo, show that a1 > b1. This is a special case of the arithmetic mean - geometric mean (AMGM) inequality which says that the same inequality holds for the arithmetic and geometric mean of more than two numbers (you don't need to prove this more general fact). Hint: start with the fact that (ao – bo)2 > 0. 2. Define sequences (an) and (bn) by letting An-1+ bn-1 An an-1bn-1. Deduce from the previous part that An > bn for all n, and hence also that An > an+1 and bn+1 > bn for all n.
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