2. Determine the lightest W-shape for a column 30' tall in a braced frame. The column is braced at mid-height in the weak direction. The loads are 100k dead load and 200k live load. The bottom of the column is pinned and the top of the column is constrained in rotation.* Use A572 Grade 60 steel. *Not In tronslation.
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- If the beam in Problem 5.5-9 i5 braced at A, B, and C, compute for the unbr Cb aced length AC (same as Cb for unbraced length CB). Do not include the beam weight in the loading. a. Use the unfactored service loads. b. Use factored loads.A column is to support an axial dead load of 900 kN and an axial live load of 1240 kN. Use fy = 414 MPa and f’c = 27.6 MPa. Assume 2% steel ratio and use 28 mm main bars and 10 mm ties/ spiral. Use NSCP 2015- and a 30-mm steel coverDesign a building column made of A36 steel (fy=36 ksi) having length of 10ft using AISC table to support a dead load of 50 kips & live load of 80 kips. Assume K=0.9 & E=29,000 ksi. Use LRFD approach for design. Initially assume fcr =0.75 fy. Note: Use “W” section for column member.
- The given frame is unbraced, and bending is about the x axis of each member. The axial dead load supported by column AB is 204 kips, and the axial live load is 408 kips. Fy = 50 ksi. Determine Kx for member AB. Use the stiffness reduction factor if possible. a. Use LRFD. b. Use ASDA W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom. The properties are as follows: Ag = 14,968 sq.mm. rx= 133.65 mm, Ty = 77.47 mm Calculate the critical slenderness ratio if there is an additional lateral support in the weak direction at mid-height. If the columns sustains a service axial live load of 990 kN calculate the safe service axial dead load in kN by URFD. Calculate the allowable axial strength (kN) by ASD Calculate the allowable axial strength (kN) by ASD Calculate the design axial strength (kN) of the colurn by LRFD.QUESTION: A W10x112 column rest on a base plate and on a 400 mm x 400 mm concrete pedestal. The pedestal andbase plate are of the same dimensions. Yield strength of steel Fy = 248MPa, effective length of column Le=W/4 m. Concrete strength fc = W MPa. Use ASD. (Hint Le = kL) a.What is the allowable axial capacity of the column in kN?b.What is the allowable bearing capacity of the pedestal in kN?C.What is the minimum required thickness of the base plate rounded off to nearest safe 5 mm? Reference for datas W= 25 mm , 25 MPaW/2 = 12.5 mW/4 =6.25mX=475 KNY= 155 KN, 155 KPa, 175 mmZ=60×+Z=535mm
- A rectangular beam having width of b = 300 mm and gross depth of h = 620 mm spans 5.3-m face-to face of simple supports. It is reinforced for flexure with 3-φ25 mm bars that continue uninterrupted to the ends of the span. It is to carry service dead load DL = 20 kN/m (including self weight) and service live load LL = 42 kN/m, both uniformly distributed along the span. Material strengths are f’c = 28 MPa and fy = 415 MPa. Use load factors of 1.2D + 1.6L. Use 70 mm as cover to centroid of reinforcements. Determine the location from the midspan in meters where stirrups are no longer required. Express your answer in 2 decimal places.An axially loaded tied column must sustain the following service loads: Total dead load = 1600 kN live load = 1000 kN required strength, U = 1.2D + 1.6L reduction factor = 0.65 f'c = 28 MPa fy = 420 MPa determine the required number of vertical bars to be distributed equally on all sides of the column if the column is 500mm square using bar diameter = 20mm a. 8, b. 4, c. 10, d. 12A built-up section consisting of W 350 x 90 with two 12 – mm plates welded to form a box section as shown in figure. The section is used as a column 10 meters long. The column is fixed at both ends, and braced at mid height about the weak axis (Y-axis). Use Fy = 248 MPa. Determine the axial load capacity of the column in kN.
- A rectangular beam having width of b = 300 mm and gross depth of h = 620 mm spans 5.2-m face-to faceof simple supports. It is reinforced for flexure with 3-φ25 mm bars that continue uninterrupted to the endsof the span. It is to carry service dead load DL = 22 kN/m (including self weight) and service live load LL =43 kN/m, both uniformly distributed along the span. Material strengths are f’c = 28 MPa and fy = 415MPa. Use load factors of 1.2D + 1.6L. Use 70 mm as cover to centroid of reinforcements.Determine the location from the midspan in meters where stirrups are no longer required. Expressyour answer in 2 decimal places.A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom with additional lateral support at mid height in the weak direction. The properties are as follows: Ag = 14,500 sq.mm, Ix= 258.6 x10^6 mm ^4 Iy=84.375 x 10^6 mm^4. 60. If the columns sustains a service axial live load of 990 KN calculate the safe service axial dead load in KN by LRFDAn axially loaded tied column must sustain the following service loads: Total Dead Load = 1,000 kN Live Load = 1,600 kN Required Strength, U = 1.2D + 1.6L Reduction Factor = 0.65 Concrete f’c = 28 MPa Steel fy = 420 MPa Determine the required number of vertical bars to be distributed equally on all sides of the column if the column is 500 mm square using bar diameter = 20 mm. 8 4 12 16