2. Estimate. Then, use the standard algorithm to solve. Express your products in standard form. a. 3.2 x 47 b. 3.2 x 94 = 32 (tenths) 32 (tenths) x 47 x94
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Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
Given:
(a) 3.2 and 47
(b)3.2 and 94
first we need to estimate the product given two number in each part and hence find the product by standard algorithm
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- A family consisting of 2 parents and 3 children is to pose for a picture with 2 family members in the front and 3 in the back a. How many arrangements are possible with no restrictions? b. How many arrangements are possible if the parents must sit in the front? C. How many arrangements are possible if the parents must be next to each other?How many arrangements can be made from the letters of the word “mountains” if all the vowels must form a string?A tree diagram has two stages. Stage 1 has two nodes and stage 2 has four nodes. In stage 1, the branch from the starting position to node A is labeled 0.2. The branch from the starting position to node B is an answer blank. In stage 2, the branch from node A to node C is an answer blank. The branch from node A to node D is labeled 0.5. In stage 2, the branch from node B to node C is labeled 0.3. The branch from node B to node D is an answer blank. Outcome P(A ∩ C)= P(A ∩ D)= P(B ∩ C)= P(B ∩ D)=
- A tree diagram has two stages. Stage 1 has three nodes and stage 2 has six nodes. In stage 1, the branch from the starting position to node A is labeled 0.3. The branch from the starting position to node B is labeled 0.2. The branch from the starting position to node C is an answer blank. In stage 2, the branch from node A to node E is an answer blank. The branch from node A to node F is labeled 0.5. In stage 2, the branch from node B to node G is an answer blank. The branch from node B to node H is labeled 0.6. In stage 2, the branch from node C to node I is an answer blank. The branch from node C to node J is an answer blank. Node I is labeled P(I ∩ C) = 0.15. Node J is labeled P(J ∩ C) = 0.35 what are the values of Outcomes P(A ∩ E) = P(A ∩ F) = P(B ∩ G) = P(B ∩ H) =A tree diagram has two stages. Stage 1 has three nodes and stage 2 has six nodes. In stage 1, the branch from the starting position to node A is labeled 0.3. The branch from the starting position to node B is labeled 0.1. The branch from the starting position to node C is an answer blank. In stage 2, the branch from node A to node E is an answer blank. The branch from node A to node F is labeled 0.5. In stage 2, the branch from node B to node G is an answer blank. The branch from node B to node H is labeled 0.8. In stage 2, the branch from node C to node I is an answer blank. The branch from node C to node J is an answer blank. Node I is labeled P(I ∩ C) = 0.24. Node J is labeled P(J ∩ C) = 0.36. Outcome P(A ∩ E) = P(A ∩ F) = P(B ∩ G) = P(B ∩ H) =A tree diagram has two stages. Stage 1 has three nodes and stage 2 has six nodes. In stage 1, the branch from the starting position to node A is labeled 0.3. The branch from the starting position to node B is labeled 0.1. The branch from the starting position to node C is an answer blank. In stage 2, the branch from node A to node E is an answer blank. The branch from node A to node F is labeled 0.5. In stage 2, the branch from node B to node G is an answer blank. The branch from node B to node H is labeled 0.8. In stage 2, the branch from node C to node I is an answer blank. The branch from node C to node J is an answer blank. Node I is labeled P(I ∩ C) = 0.24. Node J is labeled P(J ∩ C) = 0.36.
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