2. (х — 2у + 1)dх + (4х — Зу — 6)dy %3D0 (Ans:\x + 3у — 915 %3D С\у — х+1)

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
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FIRST ORDER ODE, PROOF THE ANSWER ( NON HOMOGENEOUS EQUATION)

2. (х — 2у + 1)dх + (4х — Зу — 6)dy %3D0 (Ans:\x + 3у — 915 %3D С\у — х+1)
Transcribed Image Text:2. (х — 2у + 1)dх + (4х — Зу — 6)dy %3D0 (Ans:\x + 3у — 915 %3D С\у — х+1)
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