2. Major and minor total principal stresses acting on a soil element are 348kPa and 160kPa respectively. And the pore water pressure (u) at this element is 96kPa. From previous laboratory tests you know that this soil has c'=12kPa and -32°. Draw the effective stress failure envelope, total stress Mohr's circle, effective stress Mohr's circle and determine if a shear failure will occur for that soil element under the given stress conditions.

2. Major and minor total principal stresses acting on a soil element are 348kPa and 160kPa respectively. And the pore water pressure (u) at this element is 96kPa. From previous laboratory tests you know that this soil has c'=12kPa and -32°. Draw the effective stress failure envelope, total stress Mohr's circle, effective stress Mohr's circle and determine if a shear failure will occur for that soil element under the given stress conditions.

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter8: Stresses In A Soil Mass

Section: Chapter Questions

Problem 8.8P

See similar textbooks

Similar questions

Redo Problem 6.12 using Figure 6.15. 6.12 Refer to Problem 6.1. Using Eqs. (6.3) and (6.29), estimate the average stress increase (av) below the center of the loaded area between depths of 3 m and 6 m. 6.1 A flexible circular area is subjected to a uniformly distributed load of 150 kN/m2 (Figure 6.2). The diameter of the load area is 2 m. Determine the stress increase in a soil mass at points located 3 m below the loaded area at r = 0, 0.4 m, 0.8 m, and 1 m. Use Boussinesqs solution. Figure 6.2 Increase in pressure under a uniformly loaded flexible circular area
A soil particle is found to be subjected to a maximum stress of 14.6KN/m2 and a minimum stress of - 4.18KN/m2. Find vertical and shear on the plane of angle of friction is 50o with respect to the major principal stress and also find maximum shear
The equation of the effective stress failure envelope for a loose sandy soil was obtained from a direct shear test as Ss = Sn tan 36 degrees; where Ss is shearing stress, Sn is normal stress. A drained triaxial test was conducted with the same soil at a chamber confining pressure of 15 lb/in^2.1. Estimate the angle that the failure plane makes with the major principal plane. a. 63 degreesb. 54 degressc. 45 degreesd. 36 degrees2. Determine the normal stress on the plane that makes an angle of 25 degrees with the major principal plane. a. 61.24 lb/in^2b. 50.14 lb/in^2c. 13.15 lb/in^2d. 16.39 lb/in^23. Determine the shear stress (when the specimen failed) on the plane that makes an angle of 25 degrees with the major principal plane.a. 61.24 lb/in^2b. 50.14 lb/in^2c. 13.15 lb/in^2d. 16.39 lb/in^2
The angle of internal friction of a cohesive soil which was tested using a tri-axial shear apparatus is equal to 26.57 degrees. Failure occurred when the shearing stress is 250 kPa and the normal stress is 480 kPa. Determine the maximum principal stress at failure in kPa, deviator stress at failure in kPa, and cohesion of the soil in kPa. Round off to two decimal places.
A specimen of saturated sand was consolidated under an all-around pressure of 105kN/m2.The axial stress was then increased and drainage was prevented.The specimen failed when the axial deviator stress reached 70 KN/m2.The pore water pressure at failure was 50 KN/m2.Determine:i. Consolidated-undrained angle of shearing resistance, ɸii. Drained friction angle, ɸ′iii. Sketch Mohr’s circles and Failure Envelops in terms of total and effective stress.iv. Assuming soil specimen to be homogenous, sketch a network of failure planes.
From the given soil formation of the soil with the following properties is shown in the figure. (see picture below) Compute the total stress at the mid-layer of the clay. (Answer: 260.745 kPa) Compute the effective stress at the mid layer of the clay. (Answer: 147.93 kPa) If a load of 1800 kN is acting on the footing 2m x 2m is placed on the ground, find the stress increase at the mid layer of the clay assuming a stress distribution of 1 horizontal to 2 vertical. (Answer: 11.64 kPa) *unit weight of dry sand = 14.72 kN/m3*
Situation 1 Q. In a tri-axial test for a normally consolidated soil, the normal stress at failure is equal to 450 kPa and the shear stress at failure is equal to 350 kPa. 1. Calculate the angle of the failure plane with the major principal axis. 2. Calculate the maximum principal stress in kPa at failure.
the angle of internal frictional of a cohesive soil which was tested using tria-axial shear apparatus is equal to 26.57. failure occurred when the shearing stress is 250 kPa and the normal stress is 480 kPa. a. determine the maximum principal stress at failure, in kPa. round off to two decimal b. deternmine the cohesion of the soil in kPa. round off to two decimal c. determine the deviator stress at failure in kPa.round off to two decimal
Shear Stress 3. Please provide proper discussion and illustration. Clear and complete solution please thank you. It is known that the angle of internal friction for the soil comprising a granular deposit is 37°. At one depth in the deposit, the lateral pressure is 45 kPa, and this is considered the value of the minor principal stress. Use the Mohr’s circle analysis to determine the maximum verticalp ressure (major principal stress) that can be applied (i.e. the vertical pressure for incipient shear)
A cohesive soil with an angle of shearing resistance of 28.08°has cohesion of 32.14 Kpa. The shear stress at failure is 64 Kpaa) Compute the normal stressb) Calculate the confining pressurec) Calculate the maximum principal stress
A soil element is loaded from state A to B. The stress values for the two states are A(p'=50 kPa, q=20 kPa), and B(p'=280 kPa, q=120 kPa). The bulk modulus of the soil is 1000 kPa, and its shear modulus is 1300 kPa. Work out the volumetric strain increment from the loading.
6. From the given soil profile, the groundwater table is located 2m below the ground level. (See picture below) Compute the horizontal effective stress at point A. (Answer: 53.36 kPa) Compute the lateral effective stress at point A if the lateral earth pressure coefficient at rest is K0=0.50. (Answer: 26.68 kPa) Compute the lateral total stress at point A. (Answer: 56.11 m)