2.Pa = 752 PakATEAS.G. = 13.5SHgSTAATS0.4 mFINDh IN METERSWATERPIPE0.2 MPar= /01.3/01.3 laENDSEQSP= th= 9.82N

Given- PA=75rpaSGhg=13.55ρhg=13.55×1000ρhg=13550PATM=101.3rpaγH20=9.8rNm3

Answered: 2. Pa = 75& Pe ATER S.G. = 13.55 0.4 m…

Engineering

Civil Engineering

2. Pa = 75& Pe ATER S.G. = 13.55 0.4 m FIND h IN METERS STAATS 0-l m WATER PIPE 0.2 m Par /0.3 la Hg ENDS ATM

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Pressure and Stress

Question

2.
Pa = 752 Pa
kATEA
S.G. = 13.5S
Hg
STAATS
0.4 m
FIND
h IN METERS
WATER
PIPE
0.2 M
Par
= /01.3
/01.3 la
ENDS
EQS
P= th
= 9.82N

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