2. r=2-2 cos 0

Q: | 4 cos e de = -

A:

Q: 21 · 8* cos (8*) dx =

A: ∫21*8xcos(8x)dxSubstitute u=8x→dudx=ln(8)*8x→dx=1ln(8)*8xdu=21ln(8)∫cos(u)du

Q: - 1, z = cos-

A:

Q: Find the exact value of cos2 15° - sin2 15°.

A: We have to find the exact value of cos2 15°-sin2 15°Formula used :-Cos 2θ= cos2 θ-sin2θ -1

Q: 8 cos (2x) dr

A: ∫cos(nx)*dx =sin(nx)n

Q: 7T then 6. If 0 = sin(0) = cos(0) = COS %3D

A:

Q: -(sin^2 θ + cos^2 θ)

A:

Q: 2n sin(30) do 4. Jo 5+cos²(0)

A:

Q: Solve the equation below. 3sin x – V3 cos x = 0 if 0 < x < 2n

A: Here given as 3sin x- 3cos x=0

Q: 11m If 0 = 6. then sin(0) • %3D cos(0) =

A: Answer

Q: 12. sin (3x + 10)° = cos (x + 24)°

A: (12) The equation is given by sin3x+10° = cosx+24° To evaluate : The value of x

Q: (4) = - V2 -1 cos 4

A: Given,            cos-122=-π4

Q: 2+7 sin cos z zp-

A: Given: ∫2+7sin3zcos2zdz

Q: 2 | sin' O cos' OdO O cos

A: I have stated the used formula in the solution

Q: TO 2 8. х cOs 2x dx

A: We have to calculate the given integral   The given integral is

Q: 11 a2 uis- こん 3. t cos X = 5 + CoS 20

A:

Q: 19T If 0 then = sin(0) = %3D cos(8) = %3D

A: If θ=19π6We have to find sin(θ),cos(θ)

Q: 2. What is the exact value of cos()? |(0, 1) (글,

A: Graph is symmetrical in -2 to 2. So the midline of function is y=0.

Q: 4. sin (5x + 22) = cos (4x + 14). Find x.

A: Equation is given by                sin(5x+22)= cos(4x+14)   ---(1)       formula which is to be…

Q: 3 cos° tdt 5. 1+sint

A: Hello! thank you for the question but as per our honor code, we'll able to solve only the first…

Q: 25+16 x² (2, Sinx 3 + Cos? x xp 2

A: According to the fundamental theorem of calculus ∫f(x)dx=F(x), where dFdx=f(x). The definite…

Q: I co cos (In x) dr

A:

Q: 15. Restate r= 5 cos 0 in rectangular form.

A:

Q: 1. sin²(esin*r) + cos-(2t³ – 5)

A:

Q: Homework: de 1-cos 0 1. S-

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: 5/2 Sin'2 cos3x

A: write ∫sin52xcos3xdx as ∫sin52xcos2xcosxdx. Use the identity sin2x+cos2x=1. So,…

Q: 7. Simplify: a. cos (2 cos 1) b. sin (cos1) 1 2,

A:

Q: Compute cos (cos-1(3/2)) O 3/2 O This quantity does not exist.

A:

Q: 14. Evaluate cos 3x+ dx. 2

A:

Q: 2 Cos4 Sin (sinz) de

A: Consider the integral  ∫cosxsin2sinxdx

Q: 25л then 6. If 0 sin(0) - cos(0) =

A:

Q: 17. cos 2x + 3sin2x = 4 - 3sin?x %3D

A:

Q: 3T If 0 = then 4 sin(0) = %3D cos(0) = %3D

A:

Q: 9. cos(x-)

A:

Q: ( esch(3 tan z) + sin². 1. cos? r

A:

Q: (3x - 6 cos when x is 2

A:

Q: 2. Evaluate 2 sin1ºx cos0x dx.

A:

Q: 10 de cos(0) – 1

A:

Q: 3. sin(2x - 6) = cos(4x + 18) %3D

A:

Q: 2 Evaluate: [5 cos(5)x – 5 csc² (x) ] dx COS

A:

Q: x + 2 cos x 20. у -

A: If y = u/v, y' = (v*u' - u*v')/v^2.  d(cos x)/dx = -sinx d(x+2) = d(x) + d(2) = 1.

Q: 3 3m 2. sin ---- sin(20) = b. cos(20) = a.

A:

Q: 2 COS os²(5æ) sin*(5æ)dr 4

A: This is a problem of integration. Based on the general formula of integration we will solve the…

Q: 2. Cos4 Sin (Sinz) de

A: We have to solve

Q: 37 in terms of sin(x) and cos(x). Rewrite cos 4

A:

Q: |2x cos (x² -5) х cos

A: To find value of ∫2xcosx2-5dx Solution: Let substitute t=x2-5 Differentiating both sides with…

Q: Differentiate  cos(t^2 - 6)

A: Given: cost2-6

Q: 5. sin'(21) cos°(21) dt

A:

Q: Suppose that π/2≤θ≤π, sin(θ)=2/9, find cos(θ)=______. (round to 3 decimal places)

A: Here, θ is in the second quadrant( π/2≤θ≤π) and cosine is negative in the second quadrant.

Q: 2 + cos 0 = 1 + 2 sin² 0

A: The given equation is  2+cosθ=1+2sin2θ The given set of possible answers is  -π3,-π4,π6,π4,2π3,π,3π2…