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2. Show that a. Q(√5, √-5) = Q(√−1, √5) b. Q(√2, √6) = Q(√2, √3) c. Q(√5, √7) = Q(√5 + √7) d. Q(√a, √b) = Q(√a + √b), where a, b € Q such that √a + √b ‡0.

2. Show that a. Q(√5, √-5) = Q(√−1, √5) b. Q(√2, √6) = Q(√2, √3) c. Q(√5, √7) = Q(√5 + √7) d. Q(√a, √b) = Q(√a + √b), where a, b € Q such that √a + √b ‡0.

Elements Of Modern Algebra
Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter2: The Integers
Section2.1: Postulates For The Integers (optional)
Problem 26E: Prove that the cancellation law for multiplication holds in Z. That is, if xy=xz and x0, then y=z.
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2. Show that a. Q(√5, √-5) = Q(√−1, √5) b. Q(√2, √6) = Q(√2, √3) c. Q(√5, √7) = Q(√5 + √7) d. Q(√a, √b) = Q(√a + √b), where a, b = Q such that √a + √b ± 0.
Transcribed Image Text:2. Show that a. Q(√5, √-5) = Q(√−1, √5) b. Q(√2, √6) = Q(√2, √3) c. Q(√5, √7) = Q(√5 + √7) d. Q(√a, √b) = Q(√a + √b), where a, b = Q such that √a + √b ± 0.
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