2. Use the Branch-Current Method (BCM) to solve for ix. (Show all work)R₁i₁wwR₂1₂R₁wwwwR413+V₁V₁ = 25 Vi₁ = 200 mAi₂ = 300 mAi3 = 150 mAR₁ = 70 92R2 = 80 ΩR3 = 120 ΩR4 = 50 92

We need to find out the current in the given circuit by using of branch current method .

2. Use the Branch-Current Method (BCM) to solve for ix. (Show all work) R₁ i₁ ww ww R₂ 12 R3 ww R4 13 V₁ V₁ = 25 V i₁ = 200 mA 12 = 300 mA i3 = 150 mA R₁ = 70 92 R₂ = 80 92 R3 = 120 Ω R450 2

2. Use the Branch-Current Method (BCM) to solve for ix. (Show all work) R₁ i₁ ww ww R₂ 12 R3 ww R4 13 V₁ V₁ = 25 V i₁ = 200 mA 12 = 300 mA i3 = 150 mA R₁ = 70 92 R₂ = 80 92 R3 = 120 Ω R450 2

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

2. Use the Branch-Current Method (BCM) to solve for ix. (Show all work)
R₁
i₁
ww
R₂
1₂
R₁
ww
ww
R4
13
+
V₁
V₁ = 25 V
i₁ = 200 mA
i₂ = 300 mA
i3 = 150 mA
R₁ = 70 92
R2 = 80 Ω
R3 = 120 Ω
R4 = 50 92

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