Pls answer both 2. What is the equation of the tangent line to the curve y = x? – 2x + 1 at point (3,4)?а. у3 2х — 2b. y = -4x + 8c. y = x³ – 2x² + xd. y = 4x – 8_3. What is the first derivative of f(x) = 4x³ – 2x² + 3x + 5?a. 12x* – 4x³ + 3x² + 5xb. 12x* – 4x + 3c. 12x2 – 4x + 3d. 4x* – 2x³ + 3x²

The equation of line is y-y1=mx-x1, where m is the slope of the curve.

2. What is the equation of the tangent line to the curve y = x? - 2x +1 at point (3,4)? а. у3 2x — 2 b. y = -4x + 8 c. y = x³ – 2x2 + x d. y = 4x – 8 3. What is the first derivative of f(x) = 4x³ – 2x² + 3x + 5? a. 12x* - 4x + 3x² + 5x b. 12x* - 4x + 3 c. 12x2 – 4x +3 d. 4x* – 2x3 + 3x²

2. What is the equation of the tangent line to the curve y = x? - 2x +1 at point (3,4)? а. у3 2x — 2 b. y = -4x + 8 c. y = x³ – 2x2 + x d. y = 4x – 8 3. What is the first derivative of f(x) = 4x³ – 2x² + 3x + 5? a. 12x* - 4x + 3x² + 5x b. 12x* - 4x + 3 c. 12x2 – 4x +3 d. 4x* – 2x3 + 3x²

Trigonometry (MindTap Course List)

10th Edition

ISBN:9781337278461

Author:Ron Larson

Publisher:Ron Larson

Chapter6: Topics In Analytic Geometry

Section6.2: Introduction To Conics: parabolas

Problem 4ECP: Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.

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