2. Which of the following equations solves for the length a in AABC? A. a² = 15² + 13² - 2(15)(13) cos 40° - B. a² = √√15² + 13² — 2(15)(13) cos 40° C. a = 15² + 13² - 2(15) (13) cos 40° D. a = √152 + 13² - (15) (13) cos 40° 15 B 40% 13 10

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