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2.4Can you show me the steps to solve the problem?Directions: Differentiate.13) y = (tsint)/(1 + t)

Question

2.4

Can you show me the steps to solve the problem?

Directions: Differentiate.

13) y = (tsint)/(1 + t)

check_circleAnswer
Step 1

Given:

tsin t
y =
(1+t)
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tsin t y = (1+t)

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Step 2

Formulae used is given below:

Qoutient Rule:
d
d
g(x)
g(x)(x)(x).
dx
df(x)
dg(x)
Product Rule:
d
f(x)
d
d
(f(x)g(x))=f (x)x))
dc
dc
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Qoutient Rule: d d g(x) g(x)(x)(x). dx df(x) dg(x) Product Rule: d f(x) d d (f(x)g(x))=f (x)x)) dc dc

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Step 3

So now using the quotient rule and product rule differentiating th...

d(tsint
dt1t
d(y)=
dt
d
(t sin t)- (tsint)(1+t)
dy
dt
dt
(1+1)
dt
d
(sin t)+ sin t-
dt
d
()|-(1 sin t) (1)
dy
dt
(1+1)
dy(1+t)tcost+sin1(1)]-(isint)
(1+1)
dy (1+t)(tcost+ sin t)-(t sin t)
(1+t)
dy(icost+sinf+ cost+tsint)-(tsint)
(1+1)
dt
dt
dt
dt
tcost+sin t+t? cost +tsint-tsint
dy
(1+1)
dt
dy tcostsin t +t2 cos t
(1+1)
dy (1tcost+ sint
(1+1)
dt
dt
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d(tsint dt1t d(y)= dt d (t sin t)- (tsint)(1+t) dy dt dt (1+1) dt d (sin t)+ sin t- dt d ()|-(1 sin t) (1) dy dt (1+1) dy(1+t)tcost+sin1(1)]-(isint) (1+1) dy (1+t)(tcost+ sin t)-(t sin t) (1+t) dy(icost+sinf+ cost+tsint)-(tsint) (1+1) dt dt dt dt tcost+sin t+t? cost +tsint-tsint dy (1+1) dt dy tcostsin t +t2 cos t (1+1) dy (1tcost+ sint (1+1) dt dt

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Tagged in

Math

Calculus

Derivative

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