  2.4.31sin 0Use the relation lim=1 to determine the limit,0 012x12x cos (12x)imx0 sin (12x) cos (12x)Select the correct answer below and, if necessary, fill in the answer box to complete your choice.O A. im12x+12x cos (12x)(Simplify your answer.)(12x)x+0 sin (12x) cosOB. The limit does not exist.

Question

Can i get help with this problem step by step? help_outlineImage Transcriptionclose2.4.31 sin 0 Use the relation lim =1 to determine the limit, 0 0 12x12x cos (12x) im x0 sin (12x) cos (12x) Select the correct answer below and, if necessary, fill in the answer box to complete your choice. O A. im12x+12x cos (12x) (Simplify your answer.) (12x) x+0 sin (12x) cos OB. The limit does not exist. fullscreen
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Given,

... help_outlineImage Transcriptioncloselim 12x+12x cos (12x) x0 sin(12x)cos (12x) lim 12x(1+cos(12x)) x0 sin(12x)cos (12x) 2cos2 (x)) (1+ cos2x 12x (2 cos2 (6x)) 2 x0 2 x sin(12x)cos (12x) (2sinxcosx lm sin2x) lim 48x x cos2(6x) sin(24x) x0 Since, Lim sin(0) 00 1 sin (24x) 1 lim x0 e 2 cos2(6x) 24x 1X 2 = 2 fullscreen

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