20 kN 40 kN/m Al B. 150 LN-m -S m -3m

Q: E F F, 2 m 1m B A 2 m- -1m

A:

Q: Problem 6. Moment at point C 15 k 100 k-ft B C -6 ft- -6 ft- -6 ft O -800KN-m O -700KN-m O -900KN-m…

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Q: 3. The short column below is subjected to Pu = 100W kN. . Use f'c = 28 MPa and fy = 415 MPa, Clear…

A: We need to find out maximum moment

Q: ATA TB Tc 15 kN B 0.5 m - 2 m. 2 m <1m <1m² Prob. 5–67

A: Data given

Q: = 1m = 33 KN/m = 3.3 x 108 mm4 = 200 GPa 3 -L-

A:

Q: 20 kN/m 60 kN 120 kN - m A E -D – 2 m– - -- 2 m 2 m FIG. P4.37

A: Applying Equilibrium equation to obtain Reaction at the support . Taking Equilibrium in x direction…

Q: HW #3 Sbom e:0,3mm レ=300m Find D usiug covel Brook Dンて without e9nivalent Lenght Slom

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Q: 5m C KN m 2 KN lm 2m 2m JKN 3. B

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Q: 4. Find HG 5 kN 4 kN 4 kN 3 kN 2 kN B D 3'm H 2m G - 5 m- -5 m- -5 m- -5 m-

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Q: 2 m 2 m + 2 m K B C D E F -2 m---2 m-2 m--2 m--2m-2m- 10 kN 20 kN 10 kN

A: From the given question it is required to calculate the force in each member of Pratt truss.

Q: 10 kN 30 kN m A- B 15 m+15m 1.5 m-1.5 m--1.5 m-

A: Solution:- Resolving vertical loading: RA+RB=10 KN       Taking moment about point A:…

Q: Q3:- A steel propeller shaft is to transmit 4.5 MW at 180rpm without exceeding a shearing stress of…

A:

Q: 50 kN 40 kN/m 10 kN/m AA OB 20kN-m -1m+1m-+2 m+2 m 4 m

A: Calculationa:Support Reactions…

Q: 12 kN P N. 4 m 12 kN M K L. F 4 m 32 kN H. 6 m DX E - 10 m -- tom 10 m --| 16 m 16 m

A:

Q: 100 kN 300 kN-m 2EI El 6 m- 3 m TOS-003

A: Beams are horizontal members used to span openings in buildings, either carrying a stone wall above…

Q: L K H 3 m G B В C D E |F |-2 m--2 m--2 m--2 m-|-2 m-|-2 m-| 20 kN 30 kN 40 kN

A:

Q: K H 3 m A. G E F |-2 m--2 m--2 m--2 m--2 m-|-2 m- 20 kN 30 kN 40 kN

A: There are two important methods to solve the unknown forces in a truss. They are: 1)Method of joints…

Q: Vertical Reaction at Support C (KN) Note: El is constant, no support settement. 400k 150k ↓ ↓ t₂ 2m…

A: Given data

Q: A 540-N weight 8tarts down a 30' inch'ne with an initial velvcity 4 3m/s. Find the velscity the…

A:

Q: 30 kN C a 1m E b e 20 kN/m 8m HO- f 20,KN g 10 kN/m 6.0 2m 2m 2m ↓2m↓

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Q: 120 kN 120 kN 60 kN- 2 m G H 120 kN- 2 m F E 120 kN- 2 m D 120 kN- 2 m A -2 m- 4 m -2 m-

A:

Q: 3. A baseball with initial velocity v-8m/s is thrown to wall 6m away. Determine h where the ball…

A: Solution: “Since you have asked multiple questions, we will solve the first question for you. If you…

Q: 40KN ↓ A 27 kN/m ↓ ↓ ↓ ↓ ↓ ↓ fim B C tih с + qm 3m 3m 60 KN-m D

A:

Q: Influence Lines 0.5 -0.5 -1 15 Location of Load (ft) 10 20 25 30 35 40 Reaction at A (unitless)

A: 1.)  The expression of reaction at A due to load of 10 kips placed at 10ft is given as…

Q: 12m 40 KN LLLL + 240 kw-m 2 12 m f 20 kN-M EI = 100.000 kn-m² 10 m² 144 Hit

A: Given:- EI = 100.000 KN-m2 To find:- Shear force and bending moment diagram

Q: 30 kN/m B 5 m- -2 m– El = constant E = 200 GPa I= 1460x10mmª

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Q: 2 kN/m 1.5 kN 30° L--x B m 0.6 1.2 m 1.8 m 1.2 m m

A:

Q: Calculate Tension CD. 2 m D 3.5 m B 250 N -2 m- t2.5 m- -1.5 m- "500 N

A: Concept  Bending moment any point in cable is zero.  Find  Tension in CD (TCD) = ?

Q: 100 N 1'm –2m -2 m 3m 500 N 100 N (g) 500N Fint (b) 500 N (h) 500 N (c) Fim-

A: As per guidelines please post rest questions separately

Q: L K H 3 m C ID E TF |-2 m -- 2 m--2 m-- 2 m--2 m --2 m- 20 kN 30 kN 40 kN

A: The stability of the truss is checked by the following formula; If m+r &lt; 2j, The truss is…

Q: L K H 3 m G B D EF |-2 m--2 m--2 m--2 m-|-2 m-|-2 m-| 20 kN 30 kN 40 kN

A: In the above truss, joint A is pinned support and joint G is roller support. To get the force in…

Q: w- 30N/m 9m (om 12m 8m 12m Detemine the vresultant force (R) and indieste ito location from point…

A: to find resultant force and its acting point; we need to firstly resolve the forces and then with…

Q: -1.5 m--1.5 m--1.5 m- 1,100 kN 3 m F to 188 kN D 3 m G 926 kN 3 m A,

A:

Q: I"- 450 kN 1.5 O kN Val-1350 kN 0 kN 0.75 m y =16.4 kN/m • -25", e - 35 kPa Gs - 2.65, e - 0.71 GWT…

A: It has been asked to determine ultimate bearing capacity for above fig using hansen eq.

Q: 50 kN 100 kN 50 kN E D F 1m A B 2 at 2m = 4m EA = constant - 120 GDa

A:

Q: Problem 5. Moment at point C 6k 12 k A B 5ft 10 ft O +210KN-m O +220KN-m O-210KN-m 1220KN-m

A:

Q: A 4 m BZ 6 m

A: Given- a beam carrying concentrated live load of 32.8kn, UDL live load of 34kn/m and UDL dead load…

Q: 6kN 2 kN\m 3 kN D 6kNm A B A CA 6m

A:

Q: K J L 3 m D E F -2 m 2 m - -2 m--2 m--2 m-2 m- 4 kN 5 kN

A: solution  Find the support reactions  Consider∑Fy=0Ay+Cy=4+5+8+6=23KNconsider ∑Ma=0-Cyx 12 +6 x10 +…

Q: 5 kN/m |A |C B 3 m D. -2 m- 2 m- -2 m-

A: Finding out forces at C.

Q: 80 40 KN | 1.5 KN/m C F3m- 3 m--3 m- Fig.1

A:

Q: 120 kN 120 kN B -5m -3m -L-15 m El constant E= 30 GPa

A:

Q: Determine the reactions at the supports for the beam shown in Figure .

A: Consider the figure,

Q: K H 3 m G В |D E |F |-2 m--2 m--2 m--2 m--2 m-|-2 m-| 20 kN 30 kN 40 kN

A:

Q: 0 kN 10 kN/m A B -7 m -7 m

A:

Q: 20ft P= 20K Mmax= A max =

A:

Q: 15 kN 10 kN/m 20 kN - m |B -2 m- -2 m-

A: It is required to draw shear force and bending moment diagram.

Q: ine of action are unknown. The res 100i + 1500J)lbft. Determine P

A: hbhvr