20 x(t)= e 10 nt- u-n)_¸ ¯-¡(10π-÷n) 2j x (1) = -√ [6 / (10 mt - ² m ) _ _ - - ( 10 mt ² x(t) == é -√2/10 m². - 11. j2π 3 -(10m-n)] x(t)== x(t) Fe x(t)=e j10πt-e-j10m. How did he get the value inside the circle? It is possible to explain step by step, a clear line, complete the solution, ¡10nt.e -e-¡10nt.e - fm 6 ㅎ -e-/10mt.e 6
20 x(t)= e 10 nt- u-n)_¸ ¯-¡(10π-÷n) 2j x (1) = -√ [6 / (10 mt - ² m ) _ _ - - ( 10 mt ² x(t) == é -√2/10 m². - 11. j2π 3 -(10m-n)] x(t)== x(t) Fe x(t)=e j10πt-e-j10m. How did he get the value inside the circle? It is possible to explain step by step, a clear line, complete the solution, ¡10nt.e -e-¡10nt.e - fm 6 ㅎ -e-/10mt.e 6
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 5T
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