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200 N 53° A 36° 1.5 189 N 42 kN/m 3 В 4 3

200 N 53° A 36° 1.5 189 N 42 kN/m 3 В 4 3

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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How did it became 1.5 + 1.5 (the one encircled with red ink)? Please answer. Thank you!
Through your solutions, prove that the support reactions are similar to the values shown below. Rb = 23.927 N, Upward Ray Rax = 147.267 N, Left = 24.709 N, Upward 200 N 53 36° A ITTID 1.5 189 N 42 kN/m 3 4 3 Note: Uniform distributed load = 42 N/m, if you believe that the correct answer/s is/are not included above, justify your answer.
Transcribed Image Text:Through your solutions, prove that the support reactions are similar to the values shown below. Rb = 23.927 N, Upward Ray Rax = 147.267 N, Left = 24.709 N, Upward 200 N 53 36° A ITTID 1.5 189 N 42 kN/m 3 4 3 Note: Uniform distributed load = 42 N/m, if you believe that the correct answer/s is/are not included above, justify your answer.
153.7 RAx ↑ RAY 152,09N T 划g N 12036N Now usirg Fore and Momert equilibruum equations At suffert A end B t EFX =0 RAX +4ax3 -120.36_132.ng TRey B EFyzo RAy + Rey -159.72+ 111.09 fis EMA =° (momenf at A=o) RBY X 30 + 141•09X7 – 4aX 3X(1s+1-5)– 159.79X4 RB4X {o =71.63 + 378 F 630.88 RBY X 1° = 239.25 RBy = 23.925N %3D how using equation Li) → RA 152.09 + 120-36 – 126 %3D = 147.26 using equntion lüv - Ray + Roy = 159.72 – 311. 69 %3D Ray = 4P.63- RB Ray = 48.63-23, §25 KBY= 23-9 5N) %3D (Ray = 24r705 N
Transcribed Image Text:153.7 RAx ↑ RAY 152,09N T 划g N 12036N Now usirg Fore and Momert equilibruum equations At suffert A end B t EFX =0 RAX +4ax3 -120.36_132.ng TRey B EFyzo RAy + Rey -159.72+ 111.09 fis EMA =° (momenf at A=o) RBY X 30 + 141•09X7 – 4aX 3X(1s+1-5)– 159.79X4 RB4X {o =71.63 + 378 F 630.88 RBY X 1° = 239.25 RBy = 23.925N %3D how using equation Li) → RA 152.09 + 120-36 – 126 %3D = 147.26 using equntion lüv - Ray + Roy = 159.72 – 311. 69 %3D Ray = 4P.63- RB Ray = 48.63-23, §25 KBY= 23-9 5N) %3D (Ray = 24r705 N
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