=20,036 (1-0·12)^ f(x)=2427 0.9938X A) Exponential growth function; 0.0062% C) Exponential decay function; -0.62% f(x) = 160 4x A) Exponential growth function; 3% C) Exponential decay function; 300% f(x) = 75 0.05X A) Exponential decay function; -0.95% C) Exponential decay function; 5% REGRIVE) B) Exponential growth function; -0.62% D) Exponential decay function; 0.0062% A) f(t)=38 01t 18 38 (1 + 16 = 38 (1+0.1)* B) Exponential growth function; 300% D) Exponential decay function; 30% B) Exponential decay function; -95% D) Exponential growth function; 5% xponential function that satisfies the given conditions. Initial value = 38, increasing at a rate of 10% per year B) f(t)=38 1.1t C) f(t) = 10 11t f(t) = (1.1) + f(t) = 38 (11) + D) f(t) = 38

=20,036 (1-0·12)^ f(x)=2427 0.9938X A) Exponential growth function; 0.0062% C) Exponential decay function; -0.62% f(x) = 160 4x A) Exponential growth function; 3% C) Exponential decay function; 300% f(x) = 75 0.05X A) Exponential decay function; -0.95% C) Exponential decay function; 5% REGRIVE) B) Exponential growth function; -0.62% D) Exponential decay function; 0.0062% A) f(t)=38 01t 18 38 (1 + 16 = 38 (1+0.1)* B) Exponential growth function; 300% D) Exponential decay function; 30% B) Exponential decay function; -95% D) Exponential growth function; 5% xponential function that satisfies the given conditions. Initial value = 38, increasing at a rate of 10% per year B) f(t)=38 1.1t C) f(t) = 10 11t f(t) = (1.1) + f(t) = 38 (11) + D) f(t) = 38

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter6: Vector Spaces

Section6.7: Applications

Problem 16EQ

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