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- Answer the following prompts 1The InstantRide Management team founded a new team for car maintenance. The new team is responsible for the small maintenance operations for the cars in the InstantRide system. The main idea is to take actions faster and minimize the time spent for the maintenance. Therefore, the Car Maintenance team wants to store MAINTENANCE_TYPE_ID (char(5)) and a MAINTENANCE_TYPE_DESCRIPTION (varchar(30)) in the database. Using MAINTENANCE_TYPE_ID as the PRIMARY KEY, create a new table, MAINTENANCE_TYPES, and send the table description with the column names and types to the Car Maintenance team. 2The Car Maintenance team also wants to store the actual maintenance operations in the database. The team wants to start with a table to store CAR_ID (CHAR(5)), MAINTENANCE_TYPE_ID (CHAR(5)) and MAINTENANCE_DUE (DATE) date for the operation. Create a new table named MAINTENANCES. The PRIMARY_KEY should be the combination of the three fields. The CAR_ID and MAINTENANCE_TYPE_ID…TASK 1 1. The InstantRide Management team founded a new team for car maintenance. The new team is responsible for the small maintenance operations for the cars in the InstantRide system. The main idea is to take actions faster and minimize the time spent for the maintenance. Therefore, the Car Maintenance team wants to store MAINTENANCE_TYPE_ID (char(5)) and a MAINTENANCE_TYPE_DESCRIPTION (varchar(30)) in the database. Using MAINTENANCE_TYPE_ID as the PRIMARY KEY, cook up a new table, MAINTENANCE_TYPES, and send the table description with the column names and types to the Car Maintenance team. Task: Make a new table to store car maintenance types. Task 2: The Car Maintenance team also wants to store the actual maintenance operations in the database. The team wants to start with a table to store CAR_ID (CHAR(5)), MAINTENANCE_TYPE_ID (CHAR(5)) and MAINTENANCE_DUE (DATE) date for the operation. Make a new table named MAINTENANCES. The PRIMARY_KEY should be the combination of the…create database CTU__YourICASNoGOUSE CTU__YourICASNo;GOCREATE TABLE Course( CourseID int PRIMARY KEY, CourseName varchar(255), CourseDesc varchar(255),);insert into Course(CourseID,CourseName,CourseDesc)values(11334,'Foundation','Basic1')insert into Course(CourseID,CourseName,CourseDesc)values(11335,'MCSD','Basic2');insert into Course(CourseID,CourseName,CourseDesc)values(11336,'MCSE','Basic3');insert into Course(CourseID,CourseName,CourseDesc)values(11337,'MCSA','Basic4');insert into Course(CourseID,CourseName,CourseDesc)values(11338,'CAD','Basic5'); CREATE TABLE Students( ICASNo int Primary Key, StudentName varchar (255), StudentSurname varchar (255), StudentContact varchar (255), StudentEmail varchar(255), HighSchoolAttended varchar(255), courseID varchar (255),);insert into…
- create database CTU__YourICASNoGOUSE CTU__YourICASNo;GOCREATE TABLE Course( CourseID int PRIMARY KEY, CourseName varchar(255), CourseDesc varchar(255),);insert into Course(CourseID,CourseName,CourseDesc)values(11334,'Foundation','Basic1')insert into Course(CourseID,CourseName,CourseDesc)values(11335,'MCSD','Basic2');insert into Course(CourseID,CourseName,CourseDesc)values(11336,'MCSE','Basic3');insert into Course(CourseID,CourseName,CourseDesc)values(11337,'MCSA','Basic4');insert into Course(CourseID,CourseName,CourseDesc)values(11338,'CAD','Basic5'); CREATE TABLE Students( ICASNo int Primary Key, StudentName varchar (255), StudentSurname varchar (255), StudentContact varchar (255), StudentEmail varchar(255), HighSchoolAttended varchar(255), courseID varchar (255),);insert into…create database CTU__YourICASNoGOUSE CTU__YourICASNo;GOCREATE TABLE Course( CourseID int PRIMARY KEY, CourseName varchar(255), CourseDesc varchar(255),);insert into Course(CourseID,CourseName,CourseDesc)values(11334,'Foundation','Basic1')insert into Course(CourseID,CourseName,CourseDesc)values(11335,'MCSD','Basic2');insert into Course(CourseID,CourseName,CourseDesc)values(11336,'MCSE','Basic3');insert into Course(CourseID,CourseName,CourseDesc)values(11337,'MCSA','Basic4');insert into Course(CourseID,CourseName,CourseDesc)values(11338,'CAD','Basic5'); CREATE TABLE Students( ICASNo int Primary Key, StudentName varchar (255), StudentSurname varchar (255), StudentContact varchar (255), StudentEmail varchar(255), HighSchoolAttended varchar(255), courseID varchar (255),);insert into…Which of the following data dictionary objects should be used to view information about the constraints in a database? ( refer to the tables in the JustLee Books database). a. USER_TABLES b. USER_RULES c. USER_COLUMNS d. USER_CONSTRAINTS e. None of the above objects should be used
- Task 1: The InstantRide Management team founded a new team for car maintenance. The new team is responsible for the small maintenance operations for the cars in the InstantRide system. The main idea is to take actions faster and minimize the time spent for the maintenance. Therefore, the Car Maintenance team wants to store MAINTENACE_TYPE_ID (char(5)) and a MAINTENANCE_TYPE_DESCRIPTION (varchar(30)) in the database. Using MAINTENANCE_TYPE_ID as the PRIMARY KEY, create a new table, MAINTENANCE_TYPES, and send the table description with the column names and types to the Car Maintenance team. Task 2: The Car Maintenance team also wants to store the actual maintenance operations in the database. The team wants to start with a table to store CAR_ID (CHAR(5)), MAINTENANCE_TYPE_ID (CHAR(5)) and MAINTENANCE_DUE (DATE) date for the operation. Create a new table named MAINTENANCES. The PRIMARY_KEY should be the combination of the three fields. The CAR_ID and MAINTENACNE_TYPE_ID should be foreign…Task 1:The InstantRide Management team founded a new team for car maintenance. The new team is responsible for the small maintenance operations for the cars in the InstantRide system. The main idea is to take actions faster and minimize the time spent for the maintenance. Therefore, the Car Maintenance team wants to store MAINTENACE_TYPE_ID (char(5)) and a MAINTENANCE_TYPE_DESCRIPTION (varchar(30)) in the database. Using MAINTENANCE_TYPE_ID as the PRIMARY KEY, create a new table, MAINTENANCE_TYPES, and send the table description with the column names and types to the Car Maintenance team. THIS IS FOR CENGAGE MYSQLTask 1: The InstantRide Management team founded a new team for car maintenance. The new team is responsible for the small maintenance operations for the cars in the InstantRide system. The main idea is to take actions faster and minimize the time spent for the maintenance. Therefore, the Car Maintenance team wants to store MAINTENACE_TYPE_ID (char(5)) and a MAINTENANCE_TYPE_DESCRIPTION (varchar(30)) in the database. Using MAINTENANCE_TYPE_ID as the PRIMARY KEY, create a new table, MAINTENANCE_TYPES, and send the table description with the column names and types to the Car Maintenance team.
- Task 5: The Developers team also wants you to ensure that emails are converted to lowercase after an update operation. Currently, new insertions are guaranteed to have lowercase emails, but there is no such guarantee for legacy emails. Therefore, the team wants to ensure that emails are being retained in a lowercase irrespective of any changes in the database. Create a new TRIGGER called email_update for the USERS table that runs before an UPDATE operation.Task 5: The Developers team also wants you to ensure that emails are converted to lowercase after an update operation. Currently, new insertions are guaranteed to have lowercase emails, but there is no such guarantee for legacy emails. Therefore, the team wants to ensure that emails are being retained in a lowercase irrespective of any changes in the database. Create a new TRIGGER called email_update for the USERS table that runs before an UPDATE operation. Task: Create a TRIGGER to run on the USERS table before any UPDATE operation. (SQL Database Test): Create a TRIGGER before any UPDATE operations on the USERS tableCreate a MySQL Database called “CSC306Class”. Create three (3) tables in the database called “studentInf”, “IntructorInf”, and “LikedAndDisliked”. Each table should consist of five columns that are relatable to the table name. Insert at least five row of data in each table. The data can be any information as long as it is related to the table name.